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The '''weapon target assignment problem (WTA)''' is a class of [[combinatorial optimization]] problems present in the fields of [[Optimization (mathematics)|optimization]] and [[operations research]]. It consists of finding an optimal assignment of a set of [[weapon]]s of various types to a set of targets in order to maximize the total expected damage done to the opponent.

The basic problem is as follows:

:There are a number of weapons and a number of targets. The weapons are of type <math> i = 1, \ldots, m </math>. There are <math> W_{i} </math> available weapons of type <math>i</math>. Similarly, there are <math> j = 1, \ldots, n </math> targets, each with a value of <math> V_{j} </math>. Any of the weapons can be assigned to any target. Each weapon type has a certain probability of destroying each target, given by <math> p_{ij} </math>.

Notice that as opposed to the classic [[assignment problem]] or the [[generalized assignment problem]], more than one [[agent]] (i.e., weapon) can be assigned to each ''task'' (i.e., target) and not all targets are required to have weapons assigned. Thus, we see that the WTA allows one to formulate optimal assignment problems wherein tasks require cooperation among agents. Additionally, it provides the ability to model probabilistic completion of tasks in addition to costs.

Both static and dynamic versions of WTA can be considered. In the static case, the weapons are assigned to targets once. The dynamic case involves many rounds of assignment where the state of the system after each exchange of fire (round) in considered in the next round. While the majority of work has been done on the static WTA problem, recently the dynamic WTA problem has received more attention.

==Formal mathematical definition==

The '''weapon target assignment problem''' is often formulated as the following nonlinear [[integer programming]] problem:

:<math>\min \sum_{j = 1}^n \left ( V_{j}\prod_{i = 1}^m q_{ij}^{x_{ij}} \right )</math>

subject to the constraints

:<math>\sum_{j = 1}^n x_{ij}\leq W_i \text{ for }i = 1, \ldots, m, \, </math>
:<math>x_{ij}\ge 0\text{ and integer for }i = 1, \ldots, m \text{ and }j = 1, \ldots, n.</math>

Where the variable <math>x_{ij}</math> represents the assignment of as many weapons of type <math>i</math> to target <math>j</math> and <math>q_{ij}</math> is the probability of survival (<math> 1 - p_{ij} </math>). The first constraint requires that the number of weapons of each type assigned does not exceed the number available. The second constraint is the integral constraint.

Notice that minimizing the expected survival value is the same as maximizing the expected damage.

== Algorithms and generalizations ==

It has long been known that assignment problems are [[NP-hard]]{{citation needed|date=September 2013}}. Nonetheless, an exact solution can be found using [[branch and bound]] techniques which utilize [[relaxation (approximation)]]. Many [[heuristic algorithm]]s have been proposed which provide near-optimal solutions in [[polynomial time]].<ref>Ahuja, R. et al. Exact and Heuristic Algorithms for the Weapon-Target Assignment Problem. Operations Research 55(6), pp. 1136–1146, 2007</ref>

==Example==
A commander has 5 tanks, 2 aircraft, and 1 sea vessel and is told to engage 3 targets with values 5, 10, and 20. Each weapon type has the following success probabilities against each target:
::{| class="wikitable"
|-
! Weapon Type !! <math> V_{1} = 5 </math> !! <math> V_{2} = 10 </math> !! <math> V_{3} = 20 </math>
|-
| Tank || 0.3 || 0.2 || 0.05
|-
| Aircraft || 0.1 || 0.6 || 0.5
|-
| Sea Vessel || 0.4 || 0.5 || 0.4
|}
One feasible solution is to assign the sea vessel and one aircraft to the highest valued target (3). This results in an expected survival value of <math> 20(0.6)(0.5)= 6 </math>. One could then assign the remaining aircraft and 2 tanks to target #2, resulting in expected survival value of <math> 10 (0.4)(0.8)^2 = 2.56 </math>. Finally, the remaining 3 tanks are assigned to target #1 which has an expected survival value of <math> 5 (0.7)^3 = 1.715 </math>. Thus, we have a total expected survival value of <math> 6 + 2.56 + 1.715 = 10.275 </math>.

==See also==
*[[Auction algorithm]]
*[[Closure problem]]
*[[Generalized assignment problem]]
*[[Linear bottleneck assignment problem]]
*[[Quadratic assignment problem]]
*[[Stable marriage problem]]

== References ==
{{Reflist}}

== Further reading ==
* {{cite book
| authorlink = Ravindra K. Ahuja
| first = Ravindra | last = Ahuja
| coauthors = T. L. Magnanti, J. B. Orlin
| year = 1993
| title = Network Flows
| publisher = Prentice Hall
| isbn = 0-13-617549-X
}}

[[Category:Combinatorial optimization]]
[[Category:Matching]]

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en>BD2412: /* Copper touch surfaces */Fixing links to disambiguation pages using AWB