Finite field: Difference between revisions

From formulasearchengine
Jump to navigation Jump to search
en>Mild Bill Hiccup
en>Download
m cleanup and gen fixes using AWB
 
(One intermediate revision by one other user not shown)
Line 1: Line 1:
{{For2|a '''less technical version'''|[[:simple:Feynman diagram|this article on the Simple English Wikipedia]]}}
== AzGxIk Brazil 6s 7D2rgA7u ==
{{Technical|section=|date=October 2010}}
{|style="float:right;"
|[[Image:Feynmann Diagram Gluon Radiation.svg|thumb|287px|right|In this Feynman diagram, an [[electron]] and a [[positron]] [[annihilate]], producing a [[photon]] (represented by the blue sine wave) that becomes a [[quark]]-[[antiquark]] pair, after which the antiquark radiates a [[gluon]] (represented by the green helix).]]
|}
<!-- OLD SMALLER VERSION
[[Image:Feynmann Diagram Gluon Radiation.svg|thumb|right|In this Feynman diagram, an [[electron]] and a [[positron]] [[annihilate]], producing a [[photon]] (represented by the blue sine wave) that becomes a [[quark]]-[[antiquark]] pair, after which the antiquark radiates a [[gluon]] (represented by the green helix).]]
-->
In [[theoretical physics]], '''Feynman diagrams''' are pictorial representations of the mathematical expressions governing the behavior of [[subatomic particle]]s. The scheme is named for its inventor, [[Nobel Prize]]-winning American physicist [[Richard Feynman]], and was first introduced in 1948. The interaction of sub-atomic particles can be complex and difficult to understand intuitively, and the Feynman diagrams allow for a simple visualization of what would otherwise be a rather arcane and abstract formula. As [[David Kaiser]] writes, "since the middle of the 20th century, theoretical physicists have increasingly turned to this tool to help them undertake critical calculations," and as such "Feynman diagrams have revolutionized nearly every aspect of theoretical physics".<ref>[http://web.mit.edu/dikaiser/www/FdsAmSci.pdf "Physics and Feynman's Diagrams" by David Kaiser, ''American Scientist'', Volume 93, p. 156]</ref> While the diagrams are applied primarily to [[quantum field theory]], they can also be used in other fields, such as [[solid-state physics|solid-state theory]].


Feynman proposed an interpretation of the positron as if it were an electron moving backward in time.<ref>{{cite journal |last=Feynman |first=Richard |title=The Theory of Positrons |journal=Physical Review |issue=76 |year=1949 |doi=10.1103/PhysRev.76.749 |volume=76 |pages=749|bibcode = 1949PhRv...76..749F }}</ref> Thus Feynman diagrams contain both a space axis ''and'' a time axis, and antiparticles are interpreted as moving forward in space but backward in time.
If you've tried Rhapsody in the past or you're a current subscriber, hit the comments and let me know what you think of the service. For a buck, I'm definitely [http://www.pickpm.com/pickss.php??p=14038-White-Blue-Shox-Conundrum-Online-Sale.html White Blue Shox Conundrum Online Sale] going to get my three months' worth. (If you see a different price, that means the page has defaulted back to a different seller because Click Go and Buy has run out of stock.) That is perhaps the best tablet deal I've seen to date, especially if you root that sucker to run Android 4.1. Read CNET's review of the HD+ if you want to learn more.<br><br>September poll, which found Obama leading Romney 60 percent to 38 percent among likely Massachusetts voters. That poll was done as Obama was seeing a bounce nationally after the Democratic National Convention. National polls released in mid September found Obama continuing to maintain an edge over Romney even as the race remained close. Romney was likely hurt by comments he made at a private fundraiser, in which he characterized 47 percent of Americans, who do not pay federal income taxes and who support Obama, as who feel entitled to government support. (Romney has since backed [http://www.mpif.org/partss.php??p=19734-buy-Nike-Air-Max-90-Black-Blue-for-men.html buy Nike Air Max 90 Black Blue for men] off from those comments.) On Friday, the website Real Clear Politics, which aggregates polling data, put Obama ahead of Romney nationally by three points. But Romney may win some support back after his strong performance in last week debate.<br><br>Gourcuff arrival at Stade Gerland is therefore the final piece, Aulas hopes, in a title winning puzzle.Already this term it been painfully obvious that the Rhone side were going to have issues breaking down stubborn defences. Home games against Monaco and Stade Brestois have yielded only one goal, and though that equated to four points, it hardly the dominant form that Lyon sides are used to.Admittedly an Achilles injury has prevented star forward and record signing Lisandro Lopez to feature in any form to date, and when the Argentine returns OL should boast a far more fearsome offensive line, despite the good work done by Bafetimbi Gomis in the opening month of the campaign.But Gourcuff will provide his side with another dimension from the midfield, even if his fee does look rather steep in comparison to Mesut Oezil, who switched from Werder Bremen to Real Madrid for just Worries have been correctly expressed over the playmaker recent form. <br><br>That poll pleased California Assemblyman Tom Ammiano, a San Francisco Democrat who introduced a [http://www.pickpm.com/pickss.php??p=41954-buy-cheap-Nike-Lunarglide-3-Cool-Grey-Black-Sonic-Yellow-Reflect4e-Silver-Shield-Shoes-for-women-sale.html buy cheap Nike Lunarglide 3 Cool Grey Black Sonic Yellow Reflect4e Silver Shield Shoes for women sale] bill in February to legalize marijuana in a manner similar to alcohol  taxing sales to adults while barring possession by anyone under 21. Ammiano hopes for a vote by early next year and contends the bill would generate up to $1.3 billion in revenue for his deficit plagued state.<br><br>Richard Nixon: Less than six months before he resigned amid the Watergate scandal, Nixon played piano at the Grand Ole Opry on its first night in Donelson after leaving the Ryman. He played "My Wild Irish Rose" in honor of his wife. Seigenthaler, who was backstage that night in 1974, said country music legend Roy Acuff, who had run for governor as a Republican in 1948, was "ecstatic."
相关的主题文章:
<ul>
 
  <li>[http://www.mrcroussillon.qc.ca/cgi-bin/index.cgi http://www.mrcroussillon.qc.ca/cgi-bin/index.cgi]</li>
 
  <li>[http://bouchervilletest.netc.net/cgi-bin/index.cgi http://bouchervilletest.netc.net/cgi-bin/index.cgi]</li>
 
  <li>[http://www.chinahaitong.com/bbs/forum.php?mod=viewthread&tid=5195 http://www.chinahaitong.com/bbs/forum.php?mod=viewthread&tid=5195]</li>
 
</ul>


The calculation of [[probability amplitude]]s in theoretical particle physics requires the use of rather large and complicated integrals over a large number of variables. These integrals do, however, have a regular structure, and may be represented graphically as Feynman diagrams. A Feynman diagram is a contribution of a particular class of particle paths, which join and split as described by the diagram. More precisely, and technically, a Feynman diagram is a graphical representation of a [[perturbative]] contribution to the [[transition amplitude]] or correlation function of a quantum mechanical or statistical field theory. Within the [[canonical quantization|canonical]] formulation of quantum field theory, a Feynman diagram represents a term in the [[Wick's theorem|Wick's expansion]] of the perturbative [[S-matrix]]. Alternatively, the [[path integral formulation]] of quantum field theory represents the transition amplitude as a weighted sum of all possible histories of the system from the initial to the final state, in terms of either particles or fields. The transition amplitude is then given as the matrix element of the S-matrix between the initial and the final states of the quantum system.
== dduqop World Cup Brazil 6s 7qBX6bCD ==


{{Quantum field theory}}
Sam Champion readies Weather Channel morning showFirst night a hit for 'Tonight' host Jimmy FallonFla. artist smashes $1M vase in Miami museumPlayboy Jazz Festival to celebrate George DukeBradley Cooper visits London Fashion Week Day 4First night for 'Tonight Show' host Jimmy Fallon"Green Acres"' actress Mary Grace Canfield diesBradley Cooper visits London Fashion Week Day 4The one day old barely even fidgeted as Erin Blankenship, an obstetric technician at St. <br><br>Along with significant racial and gender minority presence in its internship program, MLS is also on pace to set an attendance record in 2012 during its 10th anniversary year for MLS !Futbolito! The program is the largest touring Hispanic grassroots initiative of its kind hosted by a professional sports league, with more than 90 percent of its participants of Hispanic descent.<br><br>Police officers stand in front of wall spray painted with a message that reads in Spanish: "Franco, Coupist," referring to Paraguay's newly named President Federico Franco, in Asuncion, Paraguay, Tuesday, [http://www.ccservices.com/welcomess.php??p=5886-Nike-Shox-R4-alry-White-Black-shoe.html Nike Shox R4 alry White Black shoe] June 26, 2012. Paraguay's ousted President Fernando Lugo said Monday that he is aiming [http://www.pickpm.com/pickss.php??p=41358-buy-authentic-Nike-Shox-R4-alry-White-White-on-sale-women.html buy authentic Nike Shox R4 alry White White on sale women] to return to power and will rally allies at home and abroad after a landslide congressional vote forced him from office in what he called a break with democracy. Lugo has symbolically created a parallel Cabinet, attacking the legitimacy of the government that replaced him. (AP Photo/Jorge Saenz)<br><br>The second most important aspect is that with the Iranian sanctions getting lifted, the crude oil business is likely to remain favourable particularly for countries like India, which could have a positive impact on to the current account deficit (CAD) and on the fiscal deficit going forward, which eventually turns out to be positive on the Reserve Bank of India (RBI) monetary policies.<br><br>"The university now adheres to the institution's policy on sexual misconduct by students, which was adopted in 2013," the statement read. "The Office for Institutional Equity is the designated university office for conducting investigations into allegations of sexual misconduct involving students. In implementing university policy, OIE treats all students equally and conducts fair and impartial investigations.<br><br>Among the many features of the reception were the guest tables, which were covered with cream colored linens and decorated with tea lights and centerpieces of celebratory balloons in Jesuit blue, white, gold and silver (and done through the kindness of William and Mary Kay Zahn); buffet tables with such enticements as roast beef, crawfish Monica, muffulettas, crab cakes, fresh fruit and cheeses; and sprightly music by the Joe Simon Jazz Quartet. Provincial Lewis presented Jubilarians with personalized mementos for their service, a combined total of 980 years.<br><br>The GM plant had been the economic anchor of the community since 1919, and several of Ryan friends worked there.Working with labor and [http://www.pickpm.com/pickss.php??p=2109-Air-Max-90-White-Red-2014-For-Sale.html Air Max 90 White Red 2014 For Sale] local officials, he promoted a $200 million incentive package to try to convince GM to retool the plant from producing gas guzzling SUVs to a new line of fuel  efficient sedans.Ryan was the lone Republican among Wisconsin lawmakers who met with GM officials to make the case.In Congress, he took the fight even further when GM and Chrysler warned Washington that they could be forced to shut down completely without an infusion of government cash.On December 10, 2008, Ryan voted to steer $15 billion to the automakers  one of only 32 Republicans in the House of Representatives to do so.
相关的主题文章:
<ul>
 
  <li>[http://www.applesteps.com/Main_Page http://www.applesteps.com/Main_Page]</li>
 
  <li>[http://satellite-delight.us/index.php?title=User:Bqhpzxvdjm#VjFkqd_Jordan_6_Brazil_3vxY8ypD http://satellite-delight.us/index.php?title=User:Bqhpzxvdjm#VjFkqd_Jordan_6_Brazil_3vxY8ypD]</li>
 
  <li>[http://www.jdzchys.com/shownews.asp?id=50 http://www.jdzchys.com/shownews.asp?id=50]</li>
 
</ul>


== Motivation and history ==
== hjyEOs Brazil 6s odV2dryE ==
[[Image:Kaon-Decay.svg|301px|thumb|right|In this diagram, a [[kaon]], made of an up and anti-strange quark, decays both [[Weak interaction|weakly]] and strongly into three [[pion]]s, with intermediate steps involving a [[W and Z bosons|W boson]] and a [[gluon]] (represented by the green spiral).]]


When calculating [[scattering cross-section]]s in [[particle physics]], the interaction between particles can be described by starting from a [[free field]] that describes the incoming and outgoing particles, and including an interaction [[Hamiltonian (quantum mechanics)|Hamiltonian]] to describe how the particles deflect one another. The amplitude for scattering is the sum of each possible interaction history over all possible intermediate particle states. The number of times the interaction Hamiltonian acts is the order of the [[perturbation theory (quantum mechanics)|perturbation expansion]], and the time-dependent perturbation theory for fields is known as the [[Dyson series]]. When the intermediate states at intermediate times are energy [[Eigenvalues and eigenvectors|eigenstates]] (collections of particles with a definite momentum) the series is called [[Perturbation theory (quantum mechanics)#Time-dependent perturbation theory|old-fashioned perturbation theory]].
Everyone was going now. She was going to London. She'd never real Nike Air Max Tailwind 2010 Grey Green shop for sale find a job in Ireland, she said. The other girl said she had been to New York to see her brother. He wanted to come home on holiday, but he couldn't, as, like 100,000 other young Irish people, he was an illegal immigrant in the United States; once he left, he wouldn't be able to go back. The two fellows ladies Nike Free TR Twist Black Green at the bar talked about leaving as well. New York was the place to go; there was always work there, they said.<br><br>As a vice president and the editor of the opinion pages at The Morning Call, I'm responsible for editorials, cartoons, letters to the editor and the op ed columns. My goal is to use these features to provide a forum for readers, and I strive to be fair, available and open to everyone.<br><br>The election outcome may turn on whether Obama get out the vote ground troops can outrun Romney momentum. Polls show Romney doing considerably better among likely voters, as opposed to registered voters. That gives Obama volunteers a chance to hunt down thousands of "soft supporters," and persuade them to get to a polling place.<br><br>Want a prosecutor to be clean as the driven snow, for his allegiance to be nowhere other than with the people he serves, Turcer said. raises a lot of questions and it is a concern. My guess is they are going to have to watch oh, so very carefully, and it will also be up to the people of Hamilton County to be very watchful. <br><br>McGrath, 58, lived in Quincy, within walking distance of Mari Place, where he was a faithful participant in the Thursday night blues jam sessions helmed by guitarist Russ Costa. The memorial tribute jam is being organized by Costa, a close friend of the late saxophonist, and singer Diane Blue, in whose band he performed in recent years.<br><br>It is bad enough that the Senate Republicans have employed the tactic of filibuster to keep the economy depressed after their 12 years of control of the Congress and 8 years of control in the Executive Branch but to then want to continue on buy cheap Holiday Nike Lunar Rejuven8 Mid Black Yellow Release Dates 2015 this road of destruction in favor of political gain over the nation's business is insane. It is anti American. Party First, America whenever we get around to it policy is the crux of the Republican message.<br><br>And across Apartheid Israel. Non Western media should have totally hammered the illegality's of murdering Awlaki's family members in what appears to be a sick act of depraved revenge by Obama and nothing but.What did Awlaki's 16yr. old son do under Obama's spew of Internet Freedom which ALSO Obama ordered a UAV assassination strike on that young boy? Did the young Awlaki's son even use the Internet, he certainly didn't pick up any weapons much less use them against any Western interest nor forces but he was deliberately assassinated by Obama in what definately appears to be a WarCrime and a Crime against Humanity.Com e on Russia Today and other Non Western News Agencys, investigate the revenge assassinations ordered by President Obama on Awlaki's Family and on Osama bin Ladin's youngest Son, both are definately WarCrimes and set a dangerious level of Satanic depravity.Th e Zionist Jewish Mafia playbook of targeting the entire family of protesters is now apparently fully in play in Syria, Syria's Assad's wife and family have been repeatedly threatened by the Israeli/Obama White House, any attacks on a nations leader's wife or spouse would no doubt signal non Western forces are OK to do the same against Western leaders spouses and family members.
 
相关的主题文章:
The Dyson series can be alternatively rewritten as a sum over Feynman diagrams, where at each interaction vertex both the energy and momentum are conserved, but where the length of the energy momentum four vector is not equal to the mass. The Feynman diagrams are much easier to keep track of than old-fashioned terms, because the old-fashioned way treats the particle and antiparticle contributions as separate. Each Feynman diagram is the sum of exponentially many old-fashioned terms, because each internal line can separately represent either a particle or an antiparticle. In a non-relativistic theory, there are no antiparticles and there is no doubling, so each Feynman diagram includes only one term.
<ul>
 
 
Feynman gave a prescription for calculating the amplitude for any given diagram from a field theory [[Lagrangian]]—the [[#Feynman rules|Feynman rules]]. Each internal line corresponds to a factor of the corresponding [[virtual particle]]'s [[propagator]]; each vertex where lines meet gives a factor derived from an interaction term in the Lagrangian, and incoming and outgoing lines carry an [[energy]], [[momentum]], and [[spin (physics)|spin]].
  <li>?id=99</li>
 
 
In addition to their value as a mathematical tool, Feynman diagrams provide deep physical insight into the nature of particle interactions. Particles interact in every way available; in fact, intermediate virtual particles are allowed to propagate faster than light. The probability of each final state is then obtained by summing over all such possibilities. This is closely tied to the [[functional integral]] formulation of [[quantum mechanics]], also invented by Feynman–see [[path integral formulation]].
  <li>http://kbb.wpstaging.co.uk/activity/p/106595/</li>
 
 
The naïve application of such calculations often produces diagrams whose amplitudes are [[infinity|infinite]], because the short-distance particle interactions require a careful limiting procedure, to include particle [[self-interaction]]s. The technique of [[renormalization]], suggested by [[Ernst Stueckelberg]] and [[Hans Bethe]] and implemented by [[Freeman Dyson|Dyson]], Feynman, [[Julian Schwinger|Schwinger]], and [[Sin-Itiro Tomonaga|Tomonaga]] compensates for this effect and eliminates the troublesome infinities. After renormalization, calculations using Feynman diagrams match experimental results with very high accuracy.
  <li>?mod=viewthread&tid=57395</li>
 
 
Feynman diagram and path integral methods are also used in [[statistical mechanics]] and can even be applied to [[classical mechanics]].<ref>{{cite arXiv |author = R. Penco, D. Mauro |eprint=hep-th/0605061 |title=Perturbation theory via Feynman diagrams in classical mechanics |year=2006 |version=v2 }}</ref>
</ul>
 
=== Alternative names ===
[[Murray Gell-Mann]] always referred to Feynman diagrams as '''Stueckelberg diagrams''', after a Swiss physicist, [[Ernst Stueckelberg]], who devised a similar notation many years earlier. Stueckelberg was motivated by the need for a manifestly covariant formalism for quantum field theory, but did not provide as automated a way to handle symmetry factors and loops, although he was first to find the correct physical interpretation in terms of forward and backward in time particle paths, all without the path-integral.<ref>{{cite news |author=George Johnson |title=The Jaguar and the Fox |url=http://www.theatlantic.com/issues/2000/07/johnson.htm |work=The Atlantic |date=July 2000 |accessdate=February 26, 2013}}</ref> Historically they were sometimes called '''Feynman-Dyson diagrams''' or '''Dyson graphs''',<ref>Gribbin, John and Mary. ''Richard Feynman: A Life in Science'', Penguin-Putnam, 1997 Ch 5.</ref> because when they were introduced the path integral was unfamiliar, and [[Freeman Dyson]]'s derivation from old-fashioned perturbation theory was easier to follow for physicists trained in earlier methods. However, in 2006 Dyson himself confirmed that the diagrams should be called ''Feynman diagrams'' because "he taught us how to use them".{{Citation needed|date=April 2011}} This reflects historical fact: Feynman had to lobby hard for the diagrams which confused the establishment physicists trained in equations and graphs.<ref>Leonard Mlodinow. ''Feynman's Rainbow''. Vintage , 2011. p. 29</ref>
 
== Representation of physical reality ==
In their presentations of [[fundamental interactions]],<ref>Gerardus 't Hooft, Martinus Veltman, ''Diagrammar'', CERN Yellow Report 1973, reprinted in G. 't Hooft, ''Under the Spell of Gauge Principle'' (World Scientific, Singapore, 1994), Introduction [http://preprints.cern.ch/cgi-bin/setlink?base=cernrep&categ=Yellow_Report&id=1973-009 online]</ref><ref>Martinus Veltman, ''Diagrammatica: The Path to Feynman Diagrams'', Cambridge Lecture Notes in Physics, ISBN 0-521-45692-4</ref> written from the particle physics perspective, [[Gerard 't Hooft]] and [[Martinus Veltman]] gave good arguments for taking the original, non-regularized Feynman diagrams as the most succinct representation of our present knowledge about the physics of quantum scattering of [[fundamental particles]]. Their motivations are consistent with the convictions of [[James Daniel Bjorken]] and [[Sidney Drell]]:<ref>{{cite journal |first=J. D. |last=Bjorken |first2=S. D. |last2=Drell |title=Relativistic Quantum Fields |publisher=McGraw-Hill |location=New York |year=1965 |page=viii }}</ref> "The [[Feynman graphs]] and rules of calculation summarize [[quantum field theory]] in a form in close contact with the experimental numbers one wants to understand. Although the statement of the theory in terms of graphs may imply [[perturbation theory]], use of graphical methods in the [[many-body problem]] shows that this formalism is flexible enough to deal with phenomena of nonperturbative characters ... Some modification of the [[Feynman rules]] of calculation may well outlive the elaborate mathematical structure of local canonical quantum field theory ..." So far there are no opposing opinions. In [[quantum field theories]] the Feynman diagrams are obtained from [[Lagrangian]] by Feynman rules.
 
== Particle-path interpretation ==
A Feynman diagram is a representation of quantum field theory processes in terms of [[Elementary particle|particle]] paths. The particle trajectories are represented by the lines of the diagram, which can be squiggly or straight, with an arrow or without, depending on the type of particle. A point where lines connect to other lines is an interaction vertex, and this is where the particles meet and interact: by emitting or absorbing new particles, deflecting one another, or changing type.
 
There are three different types of lines: ''internal lines'' connect two vertices, ''incoming lines'' extend from "the past" to a vertex and represent an initial state, and ''outgoing lines'' extend from a vertex to "the future" and represent the final state. Sometimes, the bottom of the diagram is the past and the top the future; other times, the past is to the left and the future to the right. When calculating [[correlation functions]] instead of [[scattering amplitude]]s, there is no past and future and all the lines are internal. The particles then begin and end on little x's, which represent the positions of the operators whose correlation is being calculated.
 
Feynman diagrams are a pictorial representation of a contribution to the total amplitude for a process that can happen in several different ways. When a group of incoming particles are to scatter off each other, the process can be thought of as one where the particles travel over all possible paths, including paths that go backward in time.
 
Feynman diagrams are often confused with [[spacetime diagram]]s and [[bubble chamber]] images because they all describe particle scattering. Feynman diagrams are [[graph (mathematics)|graphs]] that represent the trajectories of particles in intermediate stages of a scattering process. Unlike a bubble chamber picture, only the sum of all the Feynman diagrams represent any given particle interaction; particles do not choose a particular diagram each time they interact. The law of summation is in accord with the [[quantum superposition|principle of superposition]]—every diagram contributes a factor to the total amplitude for the process.
 
== Description ==
 
[[File:Feynman diagram general properties.svg|350px|thumb|General features of the scattering process A + B → C + D:
 
• internal lines <span style="color:red;">'''(red)'''</span> for intermediate particles and processes, which has a propagator factor ("prop"), external lines <span style="color:orange;">'''(orange)'''</span> for incoming/outgoing particles to/from vertices '''(black)''',
 
• at each vertex there is 4-momentum conservation using delta functions, 4-momenta entering the vertex are positive while those leaving are negative, the factors at each vertex and internal line are multiplied in the amplitude integral,
 
• space '''x''' and time ''t'' axes are not always shown, directions of external lines correspond to passage of time.
 
]]
 
A Feynman diagram represents a perturbative contribution to the amplitude of a quantum transition from some initial quantum state to some final quantum state.
 
For example, in the process of electron-positron annihilation the initial state is one electron and one positron, the final state: two photons.
 
The initial state is often assumed to be at the left of the diagram and the final state at the right (although other conventions are also used quite often).
 
A Feynman diagram consists of points, called vertices, and lines attached to the vertices.
 
The particles in the initial state are depicted by lines sticking out in the direction of the initial state (e.g., to the left), the particles in the final state are represented by lines sticking out in the direction of the final state (e.g., to the right).
 
In [[Quantum electrodynamics|QED]] there are two types of particles: electrons/positrons (called [[fermions]]) and photons (called [[gauge bosons]]). They are represented in Feynman diagrams as follows:
# Electron in the initial state is represented by a solid line with an arrow pointing toward the vertex (→•).
# Electron in the final state is represented by a line with an arrow pointing away from the vertex: (•→).
# Positron in the initial state is represented by a solid line with an arrow pointing away from the vertex: (←•).
# Positron in the final state is represented by a line with an arrow pointing toward the vertex: (•←).
# Photon in the initial and the final state is represented by a wavy line (<big>~•</big> and <big>•~</big>).
 
In QED a vertex always has three lines attached to it: one bosonic line, one fermionic line with arrow toward the vertex, and one fermionic line with arrow away from the vertex.
 
The vertices might be connected by a bosonic or fermionic [[propagator]]. A bosonic propagator is represented by a wavy line connecting two vertices (•~•). A fermionic propagator is represented by a solid line (with an arrow in one or another direction) connecting two vertices, (•←•).
 
The number of vertices gives the order of the term in the perturbation series expansion of the transition amplitude.
 
===Electron-positron annihilation example===
[[Image:Feynman EP Annihilation.svg|thumb|Feynman Diagram of Electron-Positron Annihilation]]
 
The electron-positron annihilation interaction:
 
<math>e^+e^-\to2\gamma</math>
 
has a contribution from the second order Feynman diagram shown adjacent:
 
In the initial state (at the bottom; early time) there is one electron (e<sup>−</sup>) and one positron (e<sup>+</sup>) and in the final state (at the top; late time) there are two photons (γ).
 
{{clr}}
 
== Canonical quantization formulation ==
The [[probability amplitude]] for a transition of a quantum system from the initial state <math>|i\rangle</math> to the final state <math>|f\rangle</math> is given by the matrix element
 
:<math>S_{fi}=\langle f|S|i\rangle\;,</math>
 
where <math>S</math> is the [[S-matrix]].
 
In the canonical quantum field theory the S-matrix is represented within the [[interaction picture]] by the perturbation series in the powers of the interaction Lagrangian,
 
:<math>S=\sum_{n=0}^{\infty}{i^n\over n!}\int\prod_{j=1}^n d^4 x_j T\prod_{j=1}^n L_v(x_j)\equiv\sum_{n=0}^{\infty}S^{(n)}\;,
</math>
 
where <math>L_v</math> is the interaction Lagrangian and <math>T</math> signifies the time-ordered product of operators.
 
A Feynman diagram is a graphical representation of a term in the [[Wick's_theorem|Wick's expansion]] of the time-ordered product in the <math>n</math>-th order term <math>S^{(n)}</math> of the S-matrix,
 
:<math>T\prod_{j=1}^nL_v(x_j)=\sum_{\mathrm{all\;possible\;contractions}}(\pm)N\prod_{j=1}^nL_v(x_j)\;,</math>
 
where <math>N</math> signifies the [[Normal_order|normal-product]] of the operators and <math>(\pm)</math> takes care of the possible sign change when commuting the fermionic operators to bring them together for a contraction (a [[propagator]]).
 
=== Feynman rules ===
The diagrams are drawn according to the Feynman rules, which depend upon the interaction Lagrangian. For the [[Quantum electrodynamics|QED]] interaction Lagrangian, <math>L_v=-g\bar\psi\gamma^\mu\psi A_\mu</math>, describing the interaction of a fermionic field <math>\psi</math> with a bosonic gauge field <math>A_\mu</math>, the Feynman rules can be formulated in coordinate space as follows:
 
# Each integration coordinate <math>x_j</math> is represented by a point (sometimes called a vertex);
# A bosonic [[propagator]] is represented by a wiggly line connecting two points;
# A fermionic propagator is represented by a solid line connecting two points;
# A bosonic field <math>A_\mu(x_i)</math> is represented by a wiggly line attached to the point <math>x_i</math>;
# A fermionic field <math>\psi(x_i)</math> is represented by a solid line attached to the point <math>x_i</math> with an arrow toward the point;
# A fermionic field <math>\bar\psi(x_i)</math> is represented by a solid line attached to the point <math>x_i</math> with an arrow from the point;
 
=== Example: second order processes in QED ===
The second order perturbation term in the S-matrix is
 
:<math>S^{(2)}={(ie)^2\over 2!}\int d^4x\, d^4x'\, T\bar\psi(x)\,\gamma^\mu\,\psi(x)\,A_\mu(x)\,\bar\psi(x')\,\gamma^\nu\,\psi(x')\,A_\nu(x').\;</math>
 
==== Scattering of fermions ====
    {|align="right"
    |[[Image:Feynman-diagram-ee-scattering.png|right|thumb|360px|The Feynman diagram of the term <math>N\bar\psi(x)ie\gamma^\mu\psi(x)\bar\psi(x')ie\gamma^\nu\psi(x')\underline{A_\mu(x)A_\nu(x')}</math>]]
    |}
The Wick's expansion of the integrand gives (among others) the following term
 
<math>N\bar\psi(x)\gamma^\mu\psi(x)\bar\psi(x')\gamma^\nu\psi(x')\underline{A_\mu(x)A_\nu(x')}\;,</math>
 
where
 
<math>\underline{A_\mu(x)A_\nu(x')}=\int{d^4k\over(2\pi)^4}{-ig_{\mu\nu}\over k^2+i0}e^{-ik(x-x')}</math>
 
is the electromagnetic contraction (propagator) in the Feynman gauge. This term is represented by the Feynman diagram at the right. This diagram gives contributions to the following processes:
# <math>e^-e^-</math> scattering (initial state at the right, final state at the left of the diagram);
# <math>e^+e^+</math> scattering (initial state at the left, final state at the right of the diagram);
# <math>e^-e^+</math> scattering (initial state at the bottom/top, final state at the top/bottom of the diagram).
 
==== Compton scattering and annihilation/generation of <math>e^-e^+</math> pairs ====
Another interesting term in the expansion is
 
:<math>N\bar\psi(x)\,\gamma^\mu\,\underline{\psi(x)\,\bar\psi(x')}\,\gamma^\nu\,\psi(x')\,A_\mu(x)\,A_\nu(x')\;,</math>
 
where
 
:<math>\underline{\psi(x)\bar\psi(x')}=\int{d^4p\over(2\pi)^4}{i\over \gamma p-m+i0}e^{-ip(x-x')}</math>
 
is the fermionic contraction (propagator).
 
== Path integral formulation ==
In a path-integral, the field Lagrangian, integrated over all possible field histories, defines the probability amplitude to go from one field configuration to another. In order to make sense, the field theory should have a well-defined ground state, and the integral should be performed a little bit rotated into imaginary time.
 
=== Scalar field Lagrangian ===
A simple example is the free relativistic scalar field in d-dimensions, whose action integral is:
::<math> S = \int {1\over 2} \partial_\mu \phi \partial^\mu \phi d^dx \,.</math>
 
The probability amplitude for a process is:
 
::<math> \int_A^B e^{iS} D\phi\,, </math>
 
where A and B are space-like hypersurfaces that define the boundary conditions. The collection of all the <math>\,\phi(A)</math> on the starting hypersurface give the initial value of the field, analogous to the starting position for a point particle, and the field values <math>\,\phi(B)</math> at each point of the final hypersurface defines the final field value, which is allowed to vary, giving a different amplitude to end up at different values. This is the field-to-field transition amplitude.
 
The path integral gives the expectation value of operators between the initial and final state:
 
::<math> \int_A^B e^{iS} \phi(x_1) ... \phi(x_n) D\phi = \langle A| \phi(x_1) ... \phi(x_n) |B \rangle\,,</math>
 
and in the limit that A and B recede to the infinite past and the infinite future, the only contribution that matters is from the ground state (this is only rigorously true if the path-integral is defined slightly rotated into imaginary time). The path integral should be thought of as analogous to a probability distribution, and it is convenient to define it so that multiplying by a constant doesn't change anything:
 
::<math> {\int e^{iS} \phi(x_1) ... \phi(x_n) D\phi \over \int e^{iS} D\phi } = \langle 0 | \phi(x_1) .... \phi(x_n) |0\rangle \,.</math>
 
The normalization factor on the bottom is called the ''partition function'' for the field, and it coincides with the statistical mechanical partition function at zero temperature when rotated into imaginary time.
 
The initial-to-final amplitudes are ill-defined if one thinks of the continuum limit right from the beginning, because the fluctuations in the field can become unbounded. So the path-integral should be thought of as on a discrete square lattice, with lattice spacing <math>a</math> and the limit <math>a\rightarrow 0</math> should be taken carefully. If the final results do not depend on the shape of the lattice or the value of a, then the continuum limit exists.
 
===On a lattice ...===
On a lattice, (i), the field can be expanded in Fourier modes:
::<math>
\phi(x) = \int {dk\over (2\pi)^d} \phi(k) e^{ik\cdot x} = \int_k \phi(k) e^{ikx}\,.
</math>
 
Here the integration domain is over k restricted to a cube of side length <math>2\pi/a</math>, so that large values of k are not allowed. It is important to note that the k-measure contains the factors of <math>2\pi</math> from Fourier transforms, this is the best standard convention for k-integrals in QFT. The lattice means that fluctuations at large k are not allowed to contribute right away, they only start to contribute in the limit <math>a\rightarrow 0</math>. Sometimes, instead of a lattice, the field modes are just cut off at high values of k instead.
 
It is also convenient from time to time to consider the space-time volume to be finite, so that the k modes are also a lattice. This is not strictly as necessary as the space-lattice limit, because interactions in k are not localized, but it is convenient for keeping track of the factors in front of the k-integrals and the momentum-conserving delta functions that will arise.
 
On a lattice, (ii), the action needs to be discretized:
::<math> S= \sum_{<x,y>} {1\over 2} (\phi(x) - \phi(y) )^2\,,</math>
 
where <math><x,y></math> is a pair of nearest lattice neighbors <math>x</math> and <math>y</math>. The discretization should be thought of as defining what the derivative <math>\partial_\mu \phi</math> means.
 
In terms of the lattice Fourier modes, the action can be written:
::<math>
S= \int_k ( (1-\cos(k_1)) +(1-\cos(k_2)) + ... + (1-\cos(k_d)) )\phi^*_k \phi^k\,.
</math>
For k near zero this is:
::<math>
S = \int_k {1\over 2} k^2 |\phi(k)|^2\,.
</math>
 
Now we have the continuum Fourier transform of the original action. In finite volume, the quantity <math>d^dk</math> is not infinitesimal, but becomes the volume of a box made by neighboring Fourier modes, or <math>(2\pi/V)^d</math>.
 
The field <math>\,\phi</math> is real-valued, so the Fourier transform obeys:
 
::<math> \phi(k)^* = \phi(-k)\,.</math>
 
In terms of real and imaginary parts, the real part of <math>\,\phi(k)</math> is an [[even function]] of k, while the imaginary part is odd. The Fourier transform avoids double-counting, so that it can be written:
 
::<math> S = \int_k {1\over 2} k^2 \phi(k) \phi(-k)</math>
 
over an integration domain that integrates over each pair (k,−k) exactly once.
 
For a complex scalar field with action
 
::<math> S = \int {1\over 2} \partial_\mu\phi^* \partial^\mu\phi d^dx</math>
 
the Fourier transform is unconstrained:
 
::<math> S = \int_k {1\over 2} k^2 |\phi(k)|^2</math>
 
and the integral is over all k.
 
Integrating over all different values of <math>\,\phi(x)</math> is equivalent to integrating over all Fourier modes, because taking a Fourier transform is a unitary linear transformation of field coordinates. When you change coordinates in a multidimensional integral by a linear transformation, the value of the new integral is given by the determinant of the transformation matrix. If
::<math> y_i = A_{ij} x_j\,,</math>
 
then
::<math>
\det(A) \int dx_1 dx_2 ... dx_n = \int dy_1 dy_2 ... dy_n\,.
</math>
 
If A is a rotation, then
::<math>
A^T A = I
\,</math>
so that <math>\det A = \pm 1</math>, and the sign depends on whether the rotation includes a reflection or not.
 
The matrix that changes coordinates from <math>\,\phi(x)</math> to <math>\,\phi(k)</math> can be read off from the definition of a Fourier transform.
 
::<math> A_{kx} = e^{ikx} \,</math>
 
and the Fourier inversion theorem tells you the inverse:
 
::<math> A^{-1}_{kx} = e^{-ikx} \,</math>
 
which is the complex conjugate-transpose, up to factors of <math>2\pi</math>. On a finite volume lattice, the determinant is nonzero and independent of the field values.
::<math> \det A = 1 \,</math>
 
and the path integral is a separate factor at each value of k.
 
::<math> \int
\exp \biggl({i \over 2} \sum_k k^2 \phi^*(k) \phi(k) \biggr) D\phi = \prod_k \int_{\phi_k} e^{{i\over 2} k^2 |\phi_k|^2 d^dk} \,</math>
 
The factor <math>\scriptstyle d^dk</math> is the infinitesimal volume of a discrete cell in k-space, in a square lattice box <math>\scriptstyle d^dk = {1/L}^d</math>, where L is the side-length of the box. Each separate factor is an oscillatory Gaussian, and the width of the Gaussian diverges as the volume goes to infinity.
 
In imaginary time, the ''Euclidean action'' becomes positive definite, and can be interpreted as a probability distribution. The probability of a field having values <math>\phi_k </math> is
::<math> e^{\int_k - {1\over 2} k^2 \phi^*_k \phi_k} = \prod_k e^{- k^2 |\phi_k|^2 d^dk} </math>
 
The expectation value of the field is the statistical expectation value of the field when chosen according to the probability distribution:
 
::<math>
\langle \phi(x_1) ... \phi(x_n) \rangle = { \int e^{-S} \phi(x_1) ... \phi(x_n) D\phi \over \int e^{-S} D\phi}</math>
 
Since the probability of <math>\,\phi_k</math> is a product, the value of <math>\,\phi(k)</math> at each separate value of k is independently Gaussian distributed. The variance of the Gaussian is 1/ (k^2 d^dk), which is formally infinite, but that just means that the fluctuations are unbounded in infinite volume. In any finite volume, the integral is replaced by a discrete sum, and the variance of the integral is <math>V/k^2</math>.
 
=== Monte-Carlo ===
The path integral defines a probabilistic algorithm to generate a Euclidean scalar field configuration. Randomly pick the real and imaginary parts of each Fourier mode at wavenumber k to be a gaussian random variable with variance <math>1/k^2</math>. This generates a configuration <math>\,\phi_C(k)</math> at random, and the Fourier transform gives <math>\,\phi_C(x)</math>. For real scalar fields, the algorithm must generate only one of each pair <math>\,\phi(k),\phi(-k)</math>, and make the second the complex conjugate of the first.
 
To find any correlation function, generate a field again and again by this procedure, and find the statistical average:
 
::<math> \langle \phi(x_1) ... \phi(x_n) \rangle = \lim_{|C|\rightarrow\infty}{ \sum_C \phi_C(x_1) ... \phi_C(x_n) \over |C| } </math>
 
where <math>|C|</math> is the number of configurations, and the sum is of the product of the field values on each configuration. The Euclidean correlation function is just the same as the correlation function in statistics or statistical mechanics. The quantum mechanical correlation functions are an analytic continuation of the Euclidean correlation functions.
 
For free fields with a quadratic action, the probability distribution is a high-dimensional Gaussian, and the statistical average is given by an explicit formula. But the [[Monte Carlo method]] also works well for bosonic interacting field theories where there is no closed form for the correlation functions.
 
=== Scalar propagator ===
Each mode is independently Gaussian distributed. The expectation of field modes is easy to calculate:
 
::<math> \langle \phi_k \phi_{k'}\rangle = 0 \,</math>
 
for <math>k\ne k'</math>, since then the two Gaussian random variables are independent and both have zero mean.
 
::<math> \langle\phi_k \phi_k \rangle = {V \over k^2} </math>
 
in finite volume V, when the two k-values coincide, since this is the variance of the Gaussian. In the infinite volume limit,
 
::<math> \langle\phi(k) \phi(k')\rangle = \delta(k-k') {1\over k^2} </math>
 
Strictly speaking, this is an approximation: the lattice propagator is:
 
::<math>\langle\phi(k) \phi(k')\rangle = \delta(k-k') {1\over 2(d - \cos(k_1) + \cos(k_2) ... + \cos(k_d)) }</math>
 
But near k=0, for field fluctuations long compared to the lattice spacing, the two forms coincide.
 
It is important to emphasize that the delta functions contain factors of <math>2\pi</math>, so that they cancel out the <math>2\pi</math> factors in the measure for k integrals.
 
:: <math>\delta(k) = (2\pi)^d \delta_D(k_1)\delta_D(k_2) ... \delta_D(k_d) \,</math>
 
where <math>\delta_D(k)</math> is the ordinary one-dimensional Dirac delta function. This convention for delta-functions is not universal—some authors keep the factors of <math>2\pi</math> in the delta functions (and in the k-integration) explicit.
 
=== Equation of motion ===
The form of the propagator can be more easily found by using the equation of motion for the field. From the Lagrangian, the equation of motion is:
 
::<math> \partial_\mu \partial^\mu \phi = 0\,</math>
 
and in an expectation value, this says:
 
::<math>
\partial_\mu\partial^\mu \langle \phi(x) \phi(y)\rangle =0
</math>
 
Where the derivatives act on x, and the identity is true everywhere except when x and y coincide, and the operator order matters. The form of the singularity can be understood from the canonical commutation relations to be a delta-function. Defining the (euclidean) ''Feynman propagator'' <math>\Delta</math> as the Fourier transform of the time-ordered two-point function (the one that comes from the path-integral):
 
::<math> \partial^2 \Delta (x) = i\delta(x)\,</math>
 
So that:
 
::<math> \Delta(k) = {i\over k^2}</math>
 
If the equations of motion are linear, the propagator will always be the reciprocal of the quadratic-form matrix that defines the free Lagrangian, since this gives the equations of motion. This is also easy to see directly from the Path integral. The factor of i disappears in the Euclidean theory.
 
==== Wick theorem ====
Because each field mode is an independent Gaussian, the expectation values for the product of many field modes obeys ''Wick's theorem'':
 
::<math> \langle \phi(k_1) \phi(k_2) ... \phi(k_n)\rangle</math>
 
is zero unless the field modes coincide in pairs. This means that it is zero for an odd number of <math>\phi</math>'s, and for an even number of phi's, it is equal to a contribution from each pair separately, with a delta function.
 
::<math>\langle \phi(k_1) ... \phi(k_{2n})\rangle = \sum \prod_{i,j} {\delta(k_i - k_j) \over k_i^2 } </math>
 
where the sum is over each partition of the field modes into pairs, and the product is over the pairs. For example,
 
::<math> \langle \phi(k_1) \phi(k_2) \phi(k_3) \phi(k_4) \rangle = {\delta(k_1 -k_2) \over k_1^2}{\delta(k_3-k_4)\over k_3^2} + {\delta(k_1-k_3) \over k_3^2}{\delta(k_2-k_4)\over k_2^2} + {\delta(k_1-k_4)\over k_1^2}{\delta(k_2 -k_3)\over k_2^2}</math>
 
An interpretation of Wick's theorem is that each field insertion can be thought of as a dangling line, and the expectation value is calculated by linking up the lines in pairs, putting a delta function factor that ensures that the momentum of each partner in the pair is equal, and dividing by the propagator.
 
==== Higher Gaussian moments—completing Wick's theorem ====
There is a subtle point left before Wick's theorem is proved—what if more than two of the phis have the same momentum? If it's an odd number, the integral is zero; negative values cancel with the positive values. But if the number is even, the integral is positive. The previous demonstration assumed that the phis would only match up in pairs.
 
But the theorem is correct even when arbitrarily many of the phis are equal, and this is a notable property of Gaussian integration:
::<math> I = \int e^{-ax^2/2}dx = \sqrt{2\pi\over a} </math>
::<math> {\partial^n \over \partial a^n } I = \int {x^{2n} \over 2^n} e^{-ax^2/2}dx = {1\cdot 3 \cdot 5 ... \cdot (2n-1) \over 2 \cdot 2 \cdot 2 ... \;\;\;\;\;\cdot 2\;\;\;\;\;\;} \sqrt{2\pi} a^{-{2n+1\over2}}</math>
 
Dividing by I,
 
::<math> \langle x^{2n}\rangle={\int x^{2n} e^{-a x^2/2} \over \int e^{-a x^2/2} } = 1 \cdot 3 \cdot 5 ... \cdot (2n-1) {1\over a^n} </math>
::<math> \langle x^2 \rangle = {1\over a} </math>
 
If Wick's theorem were correct, the higher moments would be given by all possible pairings of a list of 2n x's:
 
::<math> \langle x_1 x_2 x_3 ... x_{2n} \rangle</math>
 
where the x's are all the same variable, the index is just to keep track of the number of ways to pair them. The first x can be paired with 2n−1 others, leaving 2n−2. The next unpaired x can be paired with 2n-3 different x's leaving 2n−4, and so on. This means that Wick's theorem, uncorrected, says that the expectation value of <math>x^{2n}</math> should be:
 
::<math> \langle x^{2n} \rangle = (2n-1)\cdot(2n-3).... \cdot5 \cdot 3 \cdot 1 (\langle x^2\rangle)^n </math>
 
and this is in fact the correct answer. So Wick's theorem holds no matter how many of the momenta of the internal variables coincide.
 
==== Interaction ====
Interactions are represented by higher order contributions, since quadratic contributions are always Gaussian. The simplest interaction is the quartic self-interaction, with an action:
 
::<math> S = \int \partial^\mu \phi \partial_\mu\phi + {\lambda \over 4!} \phi^4. </math>
 
The reason for the combinatorial factor 4! will be clear soon. Writing the action in terms of the lattice (or continuum) Fourier modes:
 
::<math> S = \int_k k^2 |\phi(k)|^2 + \int_{k_1k_2k_3k_4} \phi(k_1) \phi(k_2) \phi(k_3)\phi(k_4) \delta(k_1+k_2+k_3 + k_4) = S_F + X. </math>
 
Where <math>S_F</math> is the free action, whose correlation functions are given by Wick's theorem. The exponential of S in the path integral can be expanded in powers of <math>\lambda</math>, giving a series of corrections to the free action.
 
::<math> e^{-S} = e^{-S_F} ( 1 + X + {1\over 2!} X X + {1\over 3!} X X X + ... ) </math>
 
The path integral for the interacting action is then a power series of corrections to the free action. The term represented by X should be thought of as four half-lines, one for each factor of <math>\phi(k)</math>. The half-lines meet at a vertex, which contributes a delta-function that ensures that the sum of the momenta are all equal.
 
To compute a correlation function in the interacting theory, there is a contribution from the X terms now. For example, the path-integral for the four-field correlator:
 
::<math>\langle \phi(k_1) \phi(k_2) \phi(k_3) \phi(k_4) \rangle = {\int e^{-S} \phi(k_1)\phi(k_2)\phi(k_3)\phi(k_4) D\phi \over Z}</math>
 
which in the free field was only nonzero when the momenta k were equal in pairs, is now nonzero for all values of the k. The momenta of the insertions <math>\phi(k_i)</math> can now match up with the momenta of the X's in the expansion. The insertions should also be thought of as half-lines, four in this case, which carry a momentum k, but one that is not integrated.
 
The lowest order contribution comes from the first nontrivial term <math> e^{-S_F} X </math> in the Taylor expansion of the action. Wick's theorem requires that the momenta in the X half-lines, the <math>\phi(k)</math> factors in X, should match up with the momenta of the external half-lines in pairs. The new contribution is equal to:
 
::<math> \lambda {1\over k_1^2} {1\over k_2^2} {1\over k_3^2} {1\over k_4^2}. </math>
 
The 4! inside X is canceled because there are exactly 4! ways to match the half-lines in X to the external half-lines. Each of these different ways of matching the half-lines together in pairs contributes exactly once, regardless of the values of the k's, by Wick's theorem.
 
==== Feynman diagrams ====
The expansion of the action in powers of X gives a series of terms with progressively higher number of X's. The contribution from the term with exactly n X's are called n-th order.
 
The n-th order terms has:
# 4n internal half-lines, which are the factors of <math>\phi(k)</math> from the X's. These all end on a vertex, and are integrated over all possible k.
# external half-lines, which are the come from the <math>\phi(k)</math> insertions in the integral.
 
By Wick's theorem, each pair of half-lines must be paired together to make a ''line'', and this line gives a factor of
 
::<math> \delta(k_1 + k_2) \over k_1^2 </math>
 
which multiplies the contribution. This means that the two half-lines that make a line are forced to have equal and opposite momentum. The line itself should be labelled by an arrow, drawn parallel to the line, and labeled by the momentum in the line k. The half-line at the tail end of the arrow carries momentum k, while the half-line at the head-end carries momentum −k. If one of the two half-lines is external, this kills the integral over the internal k, since it forces the internal k to be equal to the external k. If both are internal, the integral over k remains.
 
The diagrams that are formed by linking the half-lines in the X's with the external half-lines, representing insertions, are the Feynman diagrams of this theory. Each line carries a factor of <math>1\over k^2</math>, the propagator, and either goes from vertex to vertex, or ends at an insertion. If it is internal, it is integrated over. At each vertex, the total incoming k is equal to the total outgoing k.
 
The number of ways of making a diagram by joining half-lines into lines almost completely cancels the factorial factors coming from the Taylor series of the exponential and the 4! at each vertex.
 
==== Loop order ====
A forest diagram is one where all the internal lines have momentum that is completely determined by the external lines and the condition that the incoming and outgoing momentum are equal at each vertex. The contribution of these diagrams is a product of propagators, without any integration. A tree diagram is a connected forest diagram.
 
An example of a tree diagram is the one where each of four external lines end on an X. Another is when three external lines end on an X, and the remaining half-line joins up with another X, and the remaining half-lines of this
X run off to external lines. These are all also forest diagrams (as every tree is a forest); an example of a forest that is not a tree is when eight external lines end on two X's.
 
It is easy to verify that in all these cases, the momenta on all the internal lines is determined by the external momenta and the condition of momentum conservation in each vertex.
 
A diagram that is not a forest diagram is called a ''loop'' diagram, and an example is one where two lines of an X are joined to external lines, while the remaining two lines are joined to each other. The two lines joined to each other can have any momentum at all, since they both enter and leave the same vertex. A more complicated example is one where two X's are joined to each other by matching the legs one to the other. This diagram has no external lines at all.
 
The reason loop diagrams are called loop diagrams is because the number of k-integrals that are left undetermined by momentum conservation is equal to the number of independent closed loops in the diagram, where independent loops are counted as in [[homology theory]]. The homology is real-valued (actually R^d valued), the value associated with each line is the momentum. The boundary operator takes each line to the sum of the end-vertices with a positive sign at the head and a negative sign at the tail. The condition that the momentum is conserved is exactly the condition that the boundary of the k-valued weighted graph is zero.
 
A set of k-values can be relabeled whenever there is a closed loop going from vertex to vertex, never revisiting the same vertex. Such a cycle can be thought of as the boundary of a 2-cell. The k-labelings of a graph that conserves momentum (which has zero boundary) up to redefinitions of k (up to boundaries of 2-cells) define the first homology of a graph. The number of independent momenta that are not determined is then equal to the number of independent homology loops. For many graphs, this is equal to the number of loops as counted in the most intuitive way.
 
==== Symmetry factors ====
The number of ways to form a given Feynman diagram by joining together half-lines is large, and by Wick's theorem, each way of pairing up the half-lines contributes equally. Often, this completely cancels the factorials in the denominator of each term, but the cancellation is sometimes incomplete.
 
The uncancelled denominator is called the ''symmetry factor'' of the diagram. The contribution of each diagram to the correlation function must be divided by its symmetry factor.
 
For example, consider the Feynman diagram formed from two external lines joined to one X, and the remaining two half-lines in the X joined to each other. There are 4×3 ways to join the external half-lines to the X, and then there is only one way to join the two remaining lines to each other. The X comes divided by 4!=4×3×2, but the number of ways to link up the X half lines to make the diagram is only 4×3, so the contribution of this diagram is divided by two.
 
For another example, consider the diagram formed by joining all the half-lines of one X to all the half-lines of another X. This diagram is called a ''vacuum bubble'', because it does not link up to any external lines. There are 4! ways to form this diagram, but the denominator includes a 2! (from the expansion of the exponential, there are two X's) and two factors of 4!. The contribution is multiplied by 4!/(2×4!×4!) = 1/48.
 
Another example is the Feynman diagram formed from two X's where each X links up to two external lines, and the remaining two half-lines of each X are joined to each other. The number of ways to link an X to two external lines is 4×3, and either X could link up to either pair, giving an additional factor of 2. The remaining two half-lines in the two X's can be linked to each other in two ways, so that the total number of ways to form the diagram is 4×3×4×3×2×2, while the denominator is 4!×4!×2!. The total symmetry factor is 2, and the contribution of this diagram is divided by 2.
 
The symmetry factor theorem gives the symmetry factor for a general diagram: the contribution of each Feynman diagram must be divided by the order of its group of automorphisms, the number of symmetries that it has.
 
An [[automorphism]] of a Feynman graph is a permutation M of the lines and a permutation N of the vertices with the following properties:
 
# If a line l goes from vertex v to vertex v', then M(l) goes from N(v) to N(v'). If the line is undirected, as it is for a real scalar field, then M(l) can go from N(v') to N(v) too.
# If a line l ends on an external line, M(l) ends on the same external line.
# If there are different types of lines, M(l) should preserve the type.
 
This theorem has an interpretation in terms of particle-paths: when identical particles are present, the integral over all intermediate particles must not double-count states that differ only by interchanging identical particles.
 
Proof: To prove this theorem, label all the internal and external lines of a diagram with a unique name. Then form the diagram by linking the a half-line to a name and then to the other half line.
 
Now count the number of ways to form the named diagram. Each permutation of the X's gives a different pattern of linking names to half-lines, and this is a factor of n!. Each permutation of the half-lines in a single X gives a factor of 4!. So a named diagram can be formed in exactly as many ways as the denominator of the Feynman expansion.
 
But the number of unnamed diagrams is smaller than the number of named diagram by the order of the automorphism group of the graph.
 
==== Connected diagrams: ''linked-cluster theorem'' ====
Roughly speaking, a Feynman diagram is called ''connected'' if all vertices and propagator lines are linked by a sequence of vertices and propagators of the diagram itself. If one views it as a [[Graph (mathematics)|(undirected) graph]] it is connected. The remarkable relevance of such diagrams in QFTs is due to the fact that they are sufficient to determine the [[Partition function (quantum field theory)|quantum partition function]] <math>Z[J]</math>. More precisely, connected Feynman diagrams determine
 
::<math>i W[J]\equiv \ln Z[J].</math>
 
To see this, one should recall that
 
::<math> Z[J]\propto\sum_k{D_k}</math>
 
with <math> D_k </math> constructed from some (arbitrary) Feynman diagram that can be thought to consist of several connected components <math> C_i </math>. If one encounters <math> n_i </math> (identical) copies of a component <math> C_i </math> within the Feynman diagram <math> D_k </math> one has to include a ''symmetry factor'' <math> n_i! </math>. However, in the end each contribution of a Feynman diagram <math> D_k </math> to the partition function has the generic form
 
::<math>\prod_i {C_{i}^{n_i} \over n_i!} </math>
 
where <math>i</math> labels the (infinite) many connected Feynman diagrams possible.
 
A scheme to successively create such contributions from the <math> D_k </math> to <math> Z[J] </math> is obtained by
 
::<math>\left(\frac{1}{0!}+\frac{C_1}{1!}+\frac{C^2_1}{2!}+\dots\right)\left(1+C_2+\frac{1}{2}C^2_2+\dots\right)\dots </math>
 
and therefore yields
 
::<math>Z[J]\propto\prod_i{\sum^\infty_{n_i=0}{\frac{C_i^{n_i}}{n_i!}}}=\exp{\sum_i{C_i}}\propto \exp{W[J]}.</math>
 
To establish the ''normalization'' <math>Z_0=\exp{W[0]}=1</math> one simply calculates all connected ''vacuum diagrams'', i.e., the diagrams without any ''sources'' <math>J</math> (sometimes referred to as ''external legs'' of a Feynman diagram).
 
==== Vacuum bubbles ====
An immediate consequence of the linked-cluster theorem is that all vacuum bubbles, diagrams without external lines, cancel when calculating correlation functions. A correlation function is given by a ratio of path-integrals:
 
::<math> \langle \phi_1(x_1) ... \phi_n(x_n)\rangle = {\int e^{-S} \phi_1(x_1) ...\phi_n(x_n) D\phi \over \int e^{-S} D\phi}.</math>
 
The top is the sum over all Feynman diagrams, including disconnected diagrams that do not link up to external lines at all. In terms of the connected diagrams, the numerator includes the same contributions of vacuum bubbles as the denominator:
 
::<math> \int e^{-S}\phi_1(x_1)...\phi_n(x_n) D\phi = (\sum E_i)( \exp(\sum_i C_i) ).</math>
 
Where the sum over E diagrams includes only those diagrams each of whose connected components end on at least one external line. The vacuum bubbles are the same whatever the external lines, and give an overall multiplicative factor. The denominator is the sum over all vacuum bubbles, and dividing gets rid of the second factor.
 
The vacuum bubbles then are only useful for determining Z itself, which from the definition of the path integral is equal to:
 
::<math> Z= \int e^{-S} D\phi = e^{-HT} = e^{-\rho V} </math>
 
where <math>\rho</math> is the energy density in the vacuum. Each vacuum bubble contains a factor of <math>\delta(k)</math> zeroing the total k at each vertex, and when there are no external lines, this contains a factor of <math>\delta(0)</math>, because the momentum conservation is over-enforced. In finite volume, this factor can be identified as the total volume of space time. Dividing by the volume, the remaining integral for the vacuum bubble has an interpretation: it is a contribution to the energy density of the vacuum.
 
==== Sources ====
Correlation functions are the sum of the connected Feynman diagrams, but the formalism treats the connected and disconnected diagrams differently. Internal lines end on vertices, while external lines go off to insertions. Introducing ''sources'' unifies the formalism, by making new vertices where one line can end.
 
Sources are external fields, fields that contribute to the action, but are not dynamical variables. A scalar field source is another scalar field h that contributes a term to the (Lorentz) Lagrangian:
 
::<math> \int h(x) \phi(x) d^dx = \int h(k) \phi(k) d^dk \,</math>
 
In the Feynman expansion, this contributes H terms with one half-line ending on a vertex. Lines in a Feynman diagram can now end either on an X vertex, or on an H-vertex, and only one line enters an H vertex. The Feynman rule for an H-vertex is that a line from an H with momentum k gets a factor of h(k).
 
The sum of the connected diagrams in the presence of sources includes a term for each connected diagram in the absence of sources, except now the diagrams can end on the source. Traditionally, a source is represented by a little "x" with one line extending out, exactly as an insertion.
 
::<math> \log(Z[h]) = \sum_{n,C} h(k_1) h(k_2) ... h(k_n) C(k_1,...,k_n)\,</math>
 
where <math> C(k_1,....,k_n) </math> is the connected diagram with n external lines carrying momentum as indicated. The sum is over all connected diagrams, as before.
 
The field h is not dynamical, which means that there is no path integral over h: h is just a parameter in the Lagrangian, which varies from point to point. The path integral for the field is:
 
::<math> Z[h] = \int e^{iS + i\int h\phi} D\phi \,</math>
 
and it is a function of the values of h at every point. One way to interpret this expression is that it is taking the Fourier transform in field space. If there is a probability density on R^n, the Fourier transform of the probability density is:
 
::<math> \int \rho(y) e^{i k y} d^n y = \langle e^{i k y} \rangle = \langle \prod_{i=1}^{n} e^{ih_i y_i}\rangle \,</math>
 
The fourier transform is the expectation of an oscillatory exponential. The path integral in the presence of a source h(x) is:
 
::<math> Z[h] = \int e^{iS} e^{i\int_x h(x)\phi(x)} D\phi = \langle e^{i h \phi }\rangle</math>
 
which, on a lattice, is the product of an oscillatory exponential for each field value:
 
::<math> \langle \prod_x e^{i h_x \phi_x}\rangle </math>
 
The fourier transform of a delta-function is a constant, which gives a formal expression for a delta function:
 
::<math> \delta(x-y) = \int e^{ik(x-y)} dk </math>
 
This tells you what a field delta function looks like in a path-integral. For two scalar fields <math>\phi</math> and <math>\eta</math>,
 
::<math> \delta(\phi - \eta) = \int e^{ i h(x)(\phi(x) -\eta(x)d^dx} Dh </math>
 
Which integrates over the Fourier transform coordinate, over h. This expression is useful for formally changing field coordinates in the path integral, much as a delta function is used to change coordinates in an ordinary multi-dimensional integral.
 
The partition function is now a function of the field h, and the physical partition function is the value when h is the zero function:
 
The correlation functions are derivatives of the path integral with respect to the source:
 
::<math> \langle\phi(x)\rangle = {1\over Z} {\partial \over \partial h(x)} Z[h] = {\partial\over\partial h(x)} \log(Z[h]).</math>
 
In Euclidean space, source contributions to the action can still appear with a factor of "i", so that they still do a Fourier transform.
 
===Spin 1/2; "photons" and "ghosts"===
 
==== Spin 1/2: Grassmann integrals ====
The field path-integral can be extended to the Fermi case, but only if the notion of integration is expanded. A [[Berezin integral|Grassmann integral]] of a free Fermi field is a high-dimensional [[determinant]] or [[Pfaffian]], which defines the new type of Gaussian integration appropriate for Fermi fields.
 
The two fundamental formulas of Grassmann integration are:
 
::<math> \int e^{M_{ij}{\bar\psi}^i \psi^j} D\bar\psi D\psi= \mathrm{Det}(M) </math>
 
where M is an arbitrary matrix and <math>\scriptstyle \psi,\bar\psi</math> are independent Grassmann variables for each index i, and
 
::<math> \int e^{{1\over 2} A_{ij} \psi^i \psi^j} D\psi = \mathrm{Pfaff}(A)</math>
 
Where A is an antisymmetric matrix, <math>\scriptstyle \psi</math> is a collection of Grassmann variables, and the 1/2 is to prevent double-counting (since <math>\scriptstyle \psi^i\psi^j = -\psi^j\psi^i</math>). In matrix notation, where <math>\scriptstyle \bar\psi</math> and <math>\scriptstyle \bar\eta</math> are Grassmann valued row vectors, <math>\scriptstyle \eta</math> and <math>\scriptstyle \psi</math> are Grassmann valued column vectors, and M is a real valued matrix:
 
::<math> Z = \int e^{\bar\psi M \psi + \bar\eta \psi + \bar\psi \eta} D\bar\psi D\psi = \int e^{(\bar\psi+\bar\eta M^{-1})M (\psi+ M^{-1}\eta) - \bar\eta M^{-1}\eta} D\bar\psi D\psi = \mathrm{Det}(M) e^{-\bar\eta M^{-1}\eta}</math>
 
Where the last equality is a consequence of the translation invariance of the Grassmann integral. The Grassmann variables <math>\eta</math> are external sources for <math>\psi</math>, and differentiating with respect to <math>\eta</math> pulls down factors of <math>\scriptstyle \bar\psi</math>.
 
::<math> \langle\bar\psi \psi\rangle = {1\over Z} {\partial \over \partial \eta} {\partial \over \partial \bar\eta} Z |_{\eta=\bar\eta=0} = M^{-1}</math>
 
again, in a schematic matrix notation. The meaning of the formula above is that the derivative with respect to the appropriate component of <math>\eta</math> and <math>\scriptstyle\bar\eta</math> gives the matrix element of <math>\scriptstyle M^{-1}</math>. This is exactly analogous to the Bosonic path integration formula for a Gaussian integral of a complex Bosonic field:
 
::<math> \int e^{\phi^* M \phi + h^* \phi + \phi^* h } D\phi^* D\phi = {e^{h^* M^{-1} h} \over \mathrm{Det}(M)}</math>
 
::<math> \langle\phi^* \phi\rangle = {1\over Z} {\partial \over \partial h} {\partial \over \partial h^*}Z |_{h=h^*=0} = M^{-1} </math>
 
So that the propagator is the inverse of the matrix in the quadratic part of the action in both the Bose and Fermi case.
 
For real Grassmann fields, for [[Majorana fermion]]s, the path integral is a Pfaffian times a source quadratic form, and the formulas give the square root of the determinant, just as they do for real Bosonic fields. The propagator is still the inverse of the quadratic part.
 
The free Dirac Lagrangian:
 
::<math> \int \bar\psi(\gamma^\mu \partial_{\mu} - m ) \psi </math>
 
formally gives the equations of motion and the anticommutation relations of the Dirac field, just as the Klein Gordon Lagrangian in an ordinary path integral gives the equations of motion and commutation relations of the scalar field. By using the spatial fourier-transform of the Dirac field as a new basis for the Grassmann algebra, the quadratic part of the Dirac action becomes simple to invert:
 
::<math> S= \int_k \bar\psi( i\gamma^\mu k_\mu - m ) \psi. </math>
 
The propagator is the inverse of the matrix M linking <math>\psi(k)</math> and <math>\scriptstyle \bar\psi(k)</math>, since different values of k do not mix together.
 
::<math> \langle\bar\psi(k') \psi (k) \rangle = \delta (k+k'){1 \over {\gamma\cdot k - m} } = \delta(k+k'){\gamma\cdot k+m \over k^2 - m^2} </math>
 
The analog of Wick's theorem matches psi and psi-bars in pairs:
 
::<math> \langle\bar\psi(k_1) \bar\psi(k_2) ... \bar\psi(k_n) \psi(k'_1) ... \psi(k_n)\rangle = \sum_{\mathrm{pairings}} (-1)^S \prod_{\mathrm{pairs}\; i,j} \delta(k_i -k_j) {1\over \gamma\cdot k_i - m}</math>
 
where S is the sign of the permutation that reorders the sequence of psi-bars and psis to put the ones that are paired up to make the delta-functions next to each other, with the psi-bar coming right before the psi. Since a psi-psi-bar pair is a commuting element of the Grassmann algebra, it doesn't matter what order the pairs are in. If more than one psi/psi-bar pair have the same k, the integral is zero, and it is easy to check that the sum over pairings gives zero in this case (there are always an even number of them). This is the Grassmann analog of the higher Gaussian moments that completed the Bosonic Wick's theorem earlier.
 
The rules for spin-1/2 Dirac particles are as follows: The propagator is the inverse of the Dirac operator, the lines have arrows just as for a complex scalar field, and the diagram acquires an overall factor of −1 for each closed Fermi loop. If there are an odd number of Fermi loops, the diagram changes sign. Historically, the −1 rule was very difficult for Feynman to discover. He discovered it after a long process of trial and error, since he lacked a proper theory of Grassmann integration.
 
The rule follows from the observation that the number of Fermi lines at a vertex is always even. Each term in the Lagrangian must always be Bosonic. A Fermi loops is counted by following Fermionic lines until one comes back to the starting point, then removing those lines from the diagram. Repeating this process eventually erases all the Fermionic lines: this is the Euler algorithm to 2-color a graph, which works whenever each vertex has even degree. Note that the number of steps in the Euler algorithm is only equal to the number of independent Fermionic homology cycles in the common special case that all terms in the Lagrangian are exactly quadratic in the Fermi fields, so that each vertex has exactly two Fermionic lines. When there are four-Fermi interactions (like in the Fermi effective theory of the Weak interactions) there are more k-integrals than Fermi loops. In this case, the counting rule should apply the Euler algorithm by pairing up the Fermi lines at each vertex into pairs that together form a bosonic factor of the term in the Lagrangian, and when entering a vertex by one line, the algorithm should always leave with the partner line.
 
To clarify and prove the rule, consider a Feynman diagram formed from vertices, terms in the Lagrangian, with Fermion fields. The full term is Bosonic, it is a commuting element of the Grassmann algebra, so the order in which the vertices appear is not important. The Fermi lines are linked into loops, and when traversing the loop, one can reorder the vertex terms one after the other as one goes around without any sign cost. The exception is when you return to the starting point, and the final half-line must be joined with the unlinked first half-line. This requires one permutation to move the last psi-bar to go in front of the first psi, and this gives the sign.
 
This rule is the only visible effect of the exclusion principle in internal lines. When there are external lines, the amplitudes are antisymmetric when two Fermi insertions for identical particles are interchanged. This is automatic in the source formalism, because the sources for Fermi fields are themselves Grassmann valued.
 
==== Spin 1: photons ====
The naive propagator for photons is infinite, since the Lagrangian for the A-field is:
 
::<math> S = \int {1\over 4} F^{\mu\nu} F_{\mu\nu} = \int - {1\over 2}(\partial^\mu A_\nu \partial_\mu A^\nu - \partial^\mu A_\mu \partial_\nu A^\nu ). \,</math>
 
The quadratic form defining the propagator is non-invertible. The reason is the [[gauge invariance]] of the field, adding a gradient to A does not change the physics.
 
To fix this problem, one needs to fix a gauge. The most convenient way is to demand that the divergence of A is some function f, whose value is random from point to point. It does no harm to integrate over the values of f, since it only determines the choice of gauge. This procedure inserts the following factor into the path integral for A:
 
::<math> \int \delta(\partial_\mu A^\mu - f) e^{-{f^2\over 2} } Df. </math>
 
The first factor, the delta function, fixes the gauge. The second factor sums over different values of f that are inequivalent gauge fixings. This is simply
 
::<math> e^{- {(\partial_\mu A_\mu)^2\over 2}}.</math>
 
The additional contribution from gauge-fixing cancels the second half of the free Lagrangian, giving the Feynman Lagrangian:
 
::<math> S= \int \partial^\mu A^\nu \partial_\mu A_\nu </math>
 
which is just like four independent free scalar fields, one for each component of A. The Feynman propagator is:
 
::<math> \langle A_\mu(k) A_\nu(k') \rangle = \delta(k+k') {g_{\mu\nu} \over k^2 }.</math>
 
The one difference is that the sign of one propagator is wrong in the Lorentz case: the timelike component has an opposite sign propagator. This means that these particle states have negative norm—they are not physical states. In the case of photons, it is easy to show by diagram methods that these states are not physical—their contribution cancels with longitudinal photons to only leave two physical photon polarization contributions for any value of k.
 
If the averaging over f is done with a coefficient different from 1/2, the two terms don't cancel completely. This gives a covariant Lagrangian with a coefficient <math>\lambda</math>, which does not affect anything:
 
::<math> S= \int {1\over 2}(\partial^\mu A^\nu \partial_\mu A_\nu - \lambda (\partial_\mu A^\mu)^2)</math>
 
and the covariant propagator for QED is:
 
::<math> \langle A_\mu(k) A_\nu(k') \rangle =\delta(k+k'){g_{\mu\nu} - \lambda{k_\mu k_\nu \over k^2} \over k^2}.</math>
 
==== Spin 1: nonabelian ghosts ====
To find the Feynman rules for nonabelian Gauge fields, the procedure that performs the Gauge fixing must be carefully corrected to account for a change of variables in the path-integral.
 
The gauge fixing factor has an extra determinant from popping the delta function:
 
::<math> \delta(\partial_\mu A_\mu - f) e^{-{f^2\over 2}} \mathrm{Det}{M} </math>
 
To find the form of the determinant, consider first a simple two-dimensional integral of a function f that depends only on r, not on the angle <math>\scriptstyle \theta</math>. Inserting an integral over theta:
 
::<math> \int f(r) dx dy = \int f(r) \int d\theta \delta(y) |{dy \over d\theta}| dx dy </math>
 
The derivative-factor ensures that popping the delta function in <math>\scriptstyle \theta</math> removes the integral. Exchanging the order of integration,
 
::<math> \int f(r) dx dy = \int d\theta \int f(r) \delta(y) |{dy\over d\theta}| dx dy </math>
 
but now the delta-function can be popped in y,
 
::<math> \int f(r) dx dy = \int d\theta_0 \int f(x) |{dy\over d\theta}| dx\,. </math>
 
The integral over <math>\scriptstyle\theta</math> just gives an overall factor of <math>\scriptstyle 2\pi</math>, while the rate of change of <math>\scriptstyle y</math> with a change in <math>\theta</math> is just x, so this exercise reproduces the standard formula for polar integration of a radial function:
 
::<math> \int f(r) dx dy = 2\pi \int f(x) x dx </math>
 
In the path-integral for a nonabelian gauge field, the analogous manipulation is:
 
::<math> \int DA \int \delta(F(A)) \mathrm{Det}({\partial F\over \partial G}) DG e^{iS} = \int DG \int \delta(F(A))\mathrm{Det}({\partial F\over \partial G}) e^{iS} \,</math>
 
The factor in front is the volume of the gauge group, and it contributes a constant, which can be discarded. The remaining integral is over the gauge fixed action.
 
::<math> \int \mathrm{Det}({\partial F\over \partial G})e^{iS_{GF}} DA \,</math>
 
To get a covariant gauge, the gauge fixing condition is the same as in the Abelian case:
 
::<math> \partial_\mu A^\mu = f \,</math>
 
Whose variation under an infinitesimal gauge transformation is given by:
 
::<math> \partial_\mu D_\mu \alpha \,</math>
 
where <math>\scriptstyle \alpha</math> is the adjoint valued element of the Lie algebra at every point that performs the infinitesimal gauge transformation. This adds the Faddeev Popov determinant to the action:
 
::<math> Det(\partial_\mu D_\mu) \,</math>
 
which can be rewritten as a Grassman integral by introducing ghost fields:
 
::<math> \int e^{\bar\eta \partial_\mu D^\mu \eta} D\bar\eta D\eta \,</math>
 
The determinant is independent of f, so the path-integral over f can give the Feynman propagator (or a covariant propagator) by choosing the measure for f as in the abelian case. The full gauge fixed action is then the Yang Mills action in Feynman gauge with an additional ghost action:
 
::<math> S= \int Tr \partial_\mu A_\nu \partial^\mu A^\nu + f^i_{jk} \partial^\nu A_i^\mu A^j_\mu A^k_\nu + f^i_{jr} f^r_{kl} A_i A_j A^k A^l + Tr \partial_\mu \bar\eta \partial^\mu \eta + \bar\eta A_j \eta \,</math>
 
The diagrams are derived from this action. The propagator for the spin-1 fields has the usual Feynman form. There are vertices of degree 3 with momentum factors whose couplings are the structure constants, and vertices of degree 4 whose couplings are products of structure constants. There are additional ghost loops, which cancel out timelike and logitudinal states in A loops.
 
In the Abelian case, the determinant for covariant gauges does not depend on A, so the ghosts do not contribute to the connected diagrams.
 
== Particle-path representation ==
Feynman diagrams were originally discovered by Feynman, by trial and error, as a way to represent the contribution to the S-matrix from different classes of particle trajectories.
 
=== Schwinger representation ===
The Euclidean scalar propagator has a suggestive representation:
 
::<math> {1\over p^2+m^2} = \int_0^\infty e^{-\tau(p^2 + m^2)} d\tau </math>
 
The meaning of this identity (which is an elementary integration) is made clearer by Fourier transforming to real space.
 
::<math> \Delta(x) = \int_0^\infty d\tau e^{-m^2\tau} {1\over ({4\pi\tau})^{d/2}}e^{-x^2\over 4\tau}</math>
 
The contribution at any one value of <math>\tau</math> to the propagator is a Gaussian of width <math>\scriptstyle \sqrt{\tau}</math>. The total propagation function from 0 to x is a weighted sum over all proper times <math>\tau</math> of a normalized Gaussian, the probability of ending up at x after a random walk of time <math>\tau</math>.
 
The path-integral representation for the propagator is then:
 
::<math> \Delta(x) = \int_0^\infty d\tau \int DX e^{- \int_0^{\tau} (\dot{x}^2/2 + m^2) d\tau'} </math>
 
which is a path-integral rewrite of the Schwinger representation.
 
The Schwinger representation is both useful for making manifest the particle aspect of the propagator, and for symmetrizing denominators of loop diagrams.
 
=== Combining denominators ===
The Schwinger representation has an immediate practical application to loop diagrams. For example, For the diagram in the phi-4 theory formed by joining two x's together in two half-lines, and making the remaining lines external, the integral over the internal propagators in the loop is:
 
:: <math> \int_k {1\over (k^2 + m^2)} {1\over ((k+p)^2 + m^2)} \,.</math>
 
Here one line carries momentum k and the other k+p. The asymmetry can be fixed by putting everything in the Schwinger representation.
 
::<math> \int_{t,t'} e^{-t(k^2+m^2) - t'((k+p)^2 +m^2) } dt dt'\,. </math>
 
Now the exponent mostly depends on t+t',
 
::<math> \int_{t,t'} e^{-(t+t')(k^2+m^2) - t' 2p\cdot k -t' p^2}\,, </math>
 
except for the asymmetrical little bit. Defining the variable u=(t+t') and <math>\scriptstyle v</math>= t'/u, the variable u goes from 0 to infinity, while <math>\scriptstyle v</math> goes from 0 to 1. The variable u is the total proper time for the loop, while <math>\scriptstyle v </math> parametrizes the fraction of the proper time on the top of the loop vs. the bottom.
 
The Jacobian for this transformation of variables is easy to work out from the identities:
 
::<math> d(uv)= dt'\;\;\;du = dt+dt'\,,</math>
 
and "wedging" gives
 
::<math> u du \wedge dv = dt \wedge dt'\,</math>.
 
This allows the u integral to be evaluated explicitly:
 
::<math> \int_{u,v} u e^{-u ( k^2+m^2 + v 2p\cdot k + v p^2)} = \int {1\over (k^2 + m^2 + v 2p\cdot k - v p^2)^2} dv </math>
 
leaving only the <math>\,v</math>-integral. This method, invented by Schwinger but usually attributed to Feynman, is called ''combining denominator''. Abstractly, it is the elementary identity:
 
::<math> {1\over AB}= \int_0^1 {1\over( vA+ (1-v)B)^2} dv </math>
 
But this form does not provide the physical motivation for introducing <math>\,v</math>—<math>\,v</math> is the proportion of proper time on one of the legs of the loop.
 
Once the denominators are combined, a shift in k to <math>k'=k+vp</math> symmetrizes everything:
 
::<math> \int_0^1 \int{1\over (k^2 + m^2 + v 2p \cdot k + v p^2)^2} dk dv = \int_0^1 \int {1\over (k'^2 + m^2 + v(1-v)p^2)^2} dk' dv</math>
 
This form shows that the moment that p<sup>2</sup> is more negative than 4 times the mass of the particle in the loop, which happens in a physical region of Lorentz space, the integral has a cut. This is exactly when the external momentum can create physical particles.
 
When the loop has more vertices, there are more denominators to combine:
 
::<math> \int dk {1\over (k^2 + m^2)} {1\over ((k+p_1)^2 + m^2)} ... {1\over ((k+p_n)^2 + m^2)}</math>
 
The general rule follows from the Schwinger prescription for n+1 denominators:
 
::<math> {1\over D_0 D_1 ... D_n} = \int_0^\infty ...\int_0^\infty e^{-u_0 D_0 ... -u_n D_n} du_0 ... du_n \,.</math>
 
The integral over the Schwinger parameters <math>\scriptstyle u_i</math> can be split up as before into an integral over the total proper time <math>\scriptstyle u = u_0 + u_1 ... + u_n </math> and an integral over the fraction of the proper time in all but the first segment of the loop <math>\scriptstyle v_i = u_i/u </math> for <math>\scriptstyle i\in \{ 1,2,...,n\}</math>. The v's are positive and add up to less than 1, so that the v integral is over an n dimensional simplex.
 
The Jacobian for the coordinate transformation can be worked out as before:
 
::<math> du = du_0 + du_1 ... + du_n \,</math>
::<math> d(uv_i) = d u_i \,.</math>
 
"Wedging" all these equation together, one obtains
 
::<math> u^n du \wedge dv_1 \wedge dv_2 ... \wedge dv_n = du_0 \wedge du_1 ... \wedge du_n \,.</math>
 
This gives the integral:
 
::<math> \int_0^\infty \int_{\mathrm{simplex}} u^n e^{-u(v_0 D_0 + v_1 D_1 + v_2 D_2 ... + v_n D_n)} dv_1 ...dv_n du\,, </math>
 
where the simplex is the region defined by the conditions <math>\scriptstyle v_i>0 </math> and <math> \scriptstyle \sum_{i=1}^n v_i < 1 </math> as well as <math>\scriptstyle v_0 = 1-\sum_{i=1}^n v_i</math>. Performing the u integral gives the general prescription for combining denominators:
 
::<math> {1\over D_0 ... D_n } = n! \int_{\mathrm{simplex}} {1\over (v_0 D_0 +v_1 D_1 ... + v_n D_n)^{n+1}} dv_1 dv_2 ... dv_n </math>
 
Since the numerator of the integrand is not involved, the same prescription works for any loop, no matter what the spins are carried by the legs. The interpretation of the parameters <math>\scriptstyle v_i </math> is that they are the fraction of the total proper time spent on each leg.
 
=== Scattering ===
The correlation functions of a quantum field theory describe the scattering of particles. The definition of "particle" in relativistic field theory is not self-evident, because if you try to determine the position so that the uncertainty is less than the [[compton wavelength]], the uncertainty in energy is large enough to produce more particles and antiparticles of the same type from the vacuum. This means that the notion of a single-particle state is to some extent incompatible with the notion of an object localized in space.
 
In the 1930s, [[Eugene Wigner|Wigner]] gave a mathematical definition for single-particle states: they are a collection of states that form an irreducible representation of the Poincaré group. Single particle states describe an object with a finite mass, a well defined momentum, and a spin. This definition is fine for protons and neutrons, electrons and photons, but it excludes quarks, which are permanently confined, so the modern point of view is more accommodating: a particle is anything whose interaction can be described in terms of Feynman diagrams, which have an interpretation as a sum over particle trajectories.
 
A field operator can act to produce a one-particle state from the vacuum, which means that the field operator <math>\phi(x)</math> produces a superposition of Wigner particle states. In the free field theory, the field produces one particle states only. But when there are interactions, the field operator can also produce 3-particle, 5-particle (if there is no +/− symmetry also 2, 4, 6 particle) states too. To compute the scattering amplitude for single particle states only requires a careful limit, sending the fields to infinity and integrating over space to get rid of the higher-order corrections.
 
The relation between scattering and correlation functions is the LSZ-theorem: The scattering amplitude for n particles to go to m-particles in a scattering event is the given by the sum of the Feynman diagrams that go into the correlation function for n+m field insertions, leaving out the propagators for the external legs.
 
For example, for the <math>\lambda \phi^4</math> interaction of the previous section, the order <math>\lambda</math> contribution to the (Lorentz) correlation function is:
 
::<math> \langle \phi(k_1)\phi(k_2)\phi(k_3)\phi(k_4)\rangle = {i\over k_1^2}{i\over k_2^2} {i\over k_3^2} {i\over k_4^2} i\lambda \,</math>
 
Stripping off the external propagators, that is, removing the factors of <math>i/k^2</math>, gives the invariant scattering amplitude M:
 
::<math> M = i\lambda \,</math>
 
which is a constant, independent of the incoming and outgoing momentum. The interpretation of the scattering amplitude is that the sum of <math>|M|^2</math> over all possible final states is the probability for the scattering event. The normalization of the single-particle states must be chosen carefully, however, to ensure that M is a relativistic invariant.
 
Non-relativistic single particle states are labeled by the momentum k, and they are chosen to have the same norm at every value of k. This is because the nonrelativistic unit operator on single particle states is:
 
::<math> \int dk |k\rangle\langle k|\, </math>
 
In relativity, the integral over the k-states for a particle of mass m integrates over a hyperbola in E,k space defined by the energy-momentum relation:
 
::<math> E^2 - k^2 = m^2 \,</math>
 
If the integral weighs each k point equally, the measure is not Lorentz invariant. The invariant measure integrates over all values of k and E, restricting to the hyperbola with a Lorentz invariant delta function:
 
::<math> \int \delta(E^2-k^2 - m^2) |E,k\rangle\langle E,k| dE dk = \int {dk \over 2 E} |k\rangle\langle k|</math>
 
So the normalized k-states are different from the relativistically normalized k-states by a factor of <math>\sqrt{E} = (k^2-m^2)^{1\over 4}</math>
 
The invariant amplitude M is then the probability amplitude for relativistically normalized incoming states to become relativistically normalized outgoing states.
 
For nonrelativistic values of k, the relativistic normalization is the same as the nonrelativistic normalization (up to a constant factor <math>\sqrt{m}</math> ). In this limit, the <math>\phi^4</math> invariant scattering amplitude is still constant. The particles created by the field phi scatter in all directions with equal amplitude.
 
The nonrelativistic potential, which scatters in all directions with an equal amplitude (in the [[Born approximation]]), is one whose Fourier transform is constant—a delta-function potential. The lowest order scattering of the theory reveals the non-relativistic interpretation of this theory—it describes a collection of particles with a delta-function repulsion. Two such particles have an aversion to occupying the same point at the same time.
 
== Nonperturbative effects ==
Thinking of Feynman diagrams as a perturbation series, nonperturbative effects like tunneling do not show up, because any effect that goes to zero faster than any polynomial does not affect the Taylor series. Even bound states are absent, since at any finite order particles are only exchanged a finite number of times, and to make a bound state, the binding force must last forever.
 
But this point of view is misleading, because the diagrams not only describe scattering, but they also are a representation of the short-distance field theory correlations. They encode not only asymptotic processes like particle scattering, they also describe the multiplication rules for fields, the [[operator product expansion]]. Nonperturbative tunneling processes involve field configurations that on average get big when the coupling constant gets small, but each configuration is a coherent superposition of particles whose local interactions are described by Feynman diagrams. When the coupling is small, these become collective processes that involve large numbers of particles, but where the interactions between each of the particles is simple.{{citation needed|date=December 2012}}
 
This means that nonperturbative effects show up asymptotically in resummations of infinite classes of diagrams, and these diagrams can be locally simple. The graphs determine the local equations of motion, while the allowed large-scale configurations describe non-perturbative physics. But because Feynman propagators are nonlocal in time, translating a field process to a coherent particle language is not completely intuitive, and has only been explicitly worked out in certain special cases. In the case of nonrelativistic bound states, the [[Bethe-Salpeter equation]] describes the class of diagrams to include to describe a relativistic atom. For quantum chromodynamics, the Shifman Vainshtein Zakharov sum rules describe non-perturbatively excited long-wavelength field modes in particle language, but only in a phenomenological way.
 
The number of Feynman diagrams at high orders of perturbation theory is very large, because there are as many diagrams as there are graphs with a given number of nodes. Nonperturbative effects leave a signature on the way in which the number of diagrams and resummations diverge at high order. It is only because non-perturbative effects appear in hidden form in diagrams that it was possible to analyze nonperturbative effects in string theory, where in many cases a Feynman description is the only one available.
 
== In popular culture ==
* The use of the above diagram of the virtual particle producing a [[quark]]-[[antiquark]] pair was featured in the television sit-com ''[[The Big Bang Theory]]'', in the episode ''"The Bat Jar Conjecture"''
* [[Phd comics]] of January 11, 2012, shows Feynman diagrams that ''visualize and describe quantum academic interactions'', i.e. the paths followed by Ph.D. students when interacting with their advisors<ref>[[Jorge Cham]], [http://www.phdcomics.com/comics.php?f=1461 Academic Interaction - Feynman Diagrams], January 11, 2012.</ref>
 
==See also==
* [[Schwinger#Schwinger and Feynman]]
* [[Stueckelberg-Feynman interpretation]]
* [[Invariance mechanics]]
* [[Penguin diagram]]
* [[Path integral formulation]]
* [[Propagator]]s
* [[JHepWork]] – a Java program for drawing Feynman diagrams using Jython/Python
* [[List of Feynman diagrams]]
* [[Angular momentum diagrams (quantum mechanics)]]
 
==Notes==
{{reflist}}
 
== References ==
* Gerardus 't Hooft, Martinus Veltman, ''Diagrammar'', CERN Yellow Report 1973, [http://preprints.cern.ch/cgi-bin/setlink?base=cernrep&categ=Yellow_Report&id=1973-009 online]
* David Kaiser, ''Drawing Theories Apart: The Dispersion of Feynman Diagrams in Postwar Physics'', Chicago: University of Chicago Press, 2005. ISBN 0-226-42266-6
* Martinus Veltman, ''Diagrammatica: The Path to Feynman Diagrams'', Cambridge Lecture Notes in Physics, ISBN 0-521-45692-4 (expanded, updated version of above)
* Mark Srednicki, ''Quantum Field Theory'', [http://www.physics.ucsb.edu/~mark/qft.html online] Script (2006)
 
== External links ==
{{commons category|Feynman diagrams}}
* [http://www.ams.org/featurecolumn/archive/feynman1.html AMS article: "What's New in Mathematics: Finite-dimensional Feynman Diagrams"]
* [http://feyndiagram.com/ Drawing Feynman diagrams with FeynDiagram] C++ library that produces PostScript output.
* [http://cnlart.web.cern.ch/cnlart/220/node60.html#SECTION00713000000000000000000 Feynman Diagram Examples] using Thorsten Ohl's Feynmf LaTeX package.
* [http://jaxodraw.sourceforge.net/ JaxoDraw] A Java program for drawing Feynman diagrams.
* {{cite web|last=Bowley|first=Roger|title=Feynman Diagrams|url=http://www.sixtysymbols.com/videos/feynman.htm|work=Sixty Symbols|publisher=[[Brady Haran]] for the [[University of Nottingham]]|coauthors=Copeland, Ed|year=2010}}
 
{{DEFAULTSORT:Feynman Diagram}}
[[Category:Concepts in physics]]
[[Category:Scattering theory]]
[[Category:Quantum field theory]]
[[Category:Diagrams]]
[[Category:Richard Feynman]]
[[Category:1948 introductions]]

Latest revision as of 07:47, 13 January 2015

AzGxIk Brazil 6s 7D2rgA7u

If you've tried Rhapsody in the past or you're a current subscriber, hit the comments and let me know what you think of the service. For a buck, I'm definitely White Blue Shox Conundrum Online Sale going to get my three months' worth. (If you see a different price, that means the page has defaulted back to a different seller because Click Go and Buy has run out of stock.) That is perhaps the best tablet deal I've seen to date, especially if you root that sucker to run Android 4.1. Read CNET's review of the HD+ if you want to learn more.

September poll, which found Obama leading Romney 60 percent to 38 percent among likely Massachusetts voters. That poll was done as Obama was seeing a bounce nationally after the Democratic National Convention. National polls released in mid September found Obama continuing to maintain an edge over Romney even as the race remained close. Romney was likely hurt by comments he made at a private fundraiser, in which he characterized 47 percent of Americans, who do not pay federal income taxes and who support Obama, as who feel entitled to government support. (Romney has since backed buy Nike Air Max 90 Black Blue for men off from those comments.) On Friday, the website Real Clear Politics, which aggregates polling data, put Obama ahead of Romney nationally by three points. But Romney may win some support back after his strong performance in last week debate.

Gourcuff arrival at Stade Gerland is therefore the final piece, Aulas hopes, in a title winning puzzle.Already this term it been painfully obvious that the Rhone side were going to have issues breaking down stubborn defences. Home games against Monaco and Stade Brestois have yielded only one goal, and though that equated to four points, it hardly the dominant form that Lyon sides are used to.Admittedly an Achilles injury has prevented star forward and record signing Lisandro Lopez to feature in any form to date, and when the Argentine returns OL should boast a far more fearsome offensive line, despite the good work done by Bafetimbi Gomis in the opening month of the campaign.But Gourcuff will provide his side with another dimension from the midfield, even if his fee does look rather steep in comparison to Mesut Oezil, who switched from Werder Bremen to Real Madrid for just Worries have been correctly expressed over the playmaker recent form.

That poll pleased California Assemblyman Tom Ammiano, a San Francisco Democrat who introduced a buy cheap Nike Lunarglide 3 Cool Grey Black Sonic Yellow Reflect4e Silver Shield Shoes for women sale bill in February to legalize marijuana in a manner similar to alcohol taxing sales to adults while barring possession by anyone under 21. Ammiano hopes for a vote by early next year and contends the bill would generate up to $1.3 billion in revenue for his deficit plagued state.

Richard Nixon: Less than six months before he resigned amid the Watergate scandal, Nixon played piano at the Grand Ole Opry on its first night in Donelson after leaving the Ryman. He played "My Wild Irish Rose" in honor of his wife. Seigenthaler, who was backstage that night in 1974, said country music legend Roy Acuff, who had run for governor as a Republican in 1948, was "ecstatic." 相关的主题文章:

dduqop World Cup Brazil 6s 7qBX6bCD

Sam Champion readies Weather Channel morning showFirst night a hit for 'Tonight' host Jimmy FallonFla. artist smashes $1M vase in Miami museumPlayboy Jazz Festival to celebrate George DukeBradley Cooper visits London Fashion Week Day 4First night for 'Tonight Show' host Jimmy Fallon"Green Acres"' actress Mary Grace Canfield diesBradley Cooper visits London Fashion Week Day 4The one day old barely even fidgeted as Erin Blankenship, an obstetric technician at St.

Along with significant racial and gender minority presence in its internship program, MLS is also on pace to set an attendance record in 2012 during its 10th anniversary year for MLS !Futbolito! The program is the largest touring Hispanic grassroots initiative of its kind hosted by a professional sports league, with more than 90 percent of its participants of Hispanic descent.

Police officers stand in front of wall spray painted with a message that reads in Spanish: "Franco, Coupist," referring to Paraguay's newly named President Federico Franco, in Asuncion, Paraguay, Tuesday, Nike Shox R4 alry White Black shoe June 26, 2012. Paraguay's ousted President Fernando Lugo said Monday that he is aiming buy authentic Nike Shox R4 alry White White on sale women to return to power and will rally allies at home and abroad after a landslide congressional vote forced him from office in what he called a break with democracy. Lugo has symbolically created a parallel Cabinet, attacking the legitimacy of the government that replaced him. (AP Photo/Jorge Saenz)

The second most important aspect is that with the Iranian sanctions getting lifted, the crude oil business is likely to remain favourable particularly for countries like India, which could have a positive impact on to the current account deficit (CAD) and on the fiscal deficit going forward, which eventually turns out to be positive on the Reserve Bank of India (RBI) monetary policies.

"The university now adheres to the institution's policy on sexual misconduct by students, which was adopted in 2013," the statement read. "The Office for Institutional Equity is the designated university office for conducting investigations into allegations of sexual misconduct involving students. In implementing university policy, OIE treats all students equally and conducts fair and impartial investigations.

Among the many features of the reception were the guest tables, which were covered with cream colored linens and decorated with tea lights and centerpieces of celebratory balloons in Jesuit blue, white, gold and silver (and done through the kindness of William and Mary Kay Zahn); buffet tables with such enticements as roast beef, crawfish Monica, muffulettas, crab cakes, fresh fruit and cheeses; and sprightly music by the Joe Simon Jazz Quartet. Provincial Lewis presented Jubilarians with personalized mementos for their service, a combined total of 980 years.

The GM plant had been the economic anchor of the community since 1919, and several of Ryan friends worked there.Working with labor and Air Max 90 White Red 2014 For Sale local officials, he promoted a $200 million incentive package to try to convince GM to retool the plant from producing gas guzzling SUVs to a new line of fuel efficient sedans.Ryan was the lone Republican among Wisconsin lawmakers who met with GM officials to make the case.In Congress, he took the fight even further when GM and Chrysler warned Washington that they could be forced to shut down completely without an infusion of government cash.On December 10, 2008, Ryan voted to steer $15 billion to the automakers one of only 32 Republicans in the House of Representatives to do so. 相关的主题文章:

hjyEOs Brazil 6s odV2dryE

Everyone was going now. She was going to London. She'd never real Nike Air Max Tailwind 2010 Grey Green shop for sale find a job in Ireland, she said. The other girl said she had been to New York to see her brother. He wanted to come home on holiday, but he couldn't, as, like 100,000 other young Irish people, he was an illegal immigrant in the United States; once he left, he wouldn't be able to go back. The two fellows ladies Nike Free TR Twist Black Green at the bar talked about leaving as well. New York was the place to go; there was always work there, they said.

As a vice president and the editor of the opinion pages at The Morning Call, I'm responsible for editorials, cartoons, letters to the editor and the op ed columns. My goal is to use these features to provide a forum for readers, and I strive to be fair, available and open to everyone.

The election outcome may turn on whether Obama get out the vote ground troops can outrun Romney momentum. Polls show Romney doing considerably better among likely voters, as opposed to registered voters. That gives Obama volunteers a chance to hunt down thousands of "soft supporters," and persuade them to get to a polling place.

Want a prosecutor to be clean as the driven snow, for his allegiance to be nowhere other than with the people he serves, Turcer said. raises a lot of questions and it is a concern. My guess is they are going to have to watch oh, so very carefully, and it will also be up to the people of Hamilton County to be very watchful.

McGrath, 58, lived in Quincy, within walking distance of Mari Place, where he was a faithful participant in the Thursday night blues jam sessions helmed by guitarist Russ Costa. The memorial tribute jam is being organized by Costa, a close friend of the late saxophonist, and singer Diane Blue, in whose band he performed in recent years.

It is bad enough that the Senate Republicans have employed the tactic of filibuster to keep the economy depressed after their 12 years of control of the Congress and 8 years of control in the Executive Branch but to then want to continue on buy cheap Holiday Nike Lunar Rejuven8 Mid Black Yellow Release Dates 2015 this road of destruction in favor of political gain over the nation's business is insane. It is anti American. Party First, America whenever we get around to it policy is the crux of the Republican message.

And across Apartheid Israel. Non Western media should have totally hammered the illegality's of murdering Awlaki's family members in what appears to be a sick act of depraved revenge by Obama and nothing but.What did Awlaki's 16yr. old son do under Obama's spew of Internet Freedom which ALSO Obama ordered a UAV assassination strike on that young boy? Did the young Awlaki's son even use the Internet, he certainly didn't pick up any weapons much less use them against any Western interest nor forces but he was deliberately assassinated by Obama in what definately appears to be a WarCrime and a Crime against Humanity.Com e on Russia Today and other Non Western News Agencys, investigate the revenge assassinations ordered by President Obama on Awlaki's Family and on Osama bin Ladin's youngest Son, both are definately WarCrimes and set a dangerious level of Satanic depravity.Th e Zionist Jewish Mafia playbook of targeting the entire family of protesters is now apparently fully in play in Syria, Syria's Assad's wife and family have been repeatedly threatened by the Israeli/Obama White House, any attacks on a nations leader's wife or spouse would no doubt signal non Western forces are OK to do the same against Western leaders spouses and family members. 相关的主题文章: