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| In [[physics]], the '''center-of-momentum frame''' ('''zero-momentum frame''', or '''COM frame''') of a system is the unique [[inertial frame]] in which the [[center of mass]] of the system is at rest. The total [[momentum]] of the system vanishes in this reference frame. The ''center of momentum'' of a system is not a location, but usually refers to the coordinate reference frame in which the momenta of a system's components add to zero. Thus "center of momentum" already means "center-of-momentum '''frame'''" and is a short form of this phrase.<ref>Dynamics and Relativity, J.R. Forshaw, A.G. Smith, Wiley, 2009, ISBN 978-0-470-01460-8</ref>
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| A special case of the center-of-momentum frame is the '''center-of-mass frame''': an inertial frame in which the [[center of mass]] (which is a physical point) is at the origin at all times. In all COM frames, the center of mass is at rest, but it may not necessarily be at rest at the origin of the coordinate system.
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| ==Properties==
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| ===General===
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| The center of momentum frame is defined as the inertial frame in which the sum over the linear momentum of each particle vanishes.
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| Let <math>S</math> denote the lab reference system and <math>S'</math> denote the center of momentum reference frame.
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| Quantities in <math>S'</math> are denoted by a prime. Using a [[galilean transformation]], the particle
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| velocity in <math>S'</math> is
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| <math> v' = v - V_c, </math>
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| where
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| <math>
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| V_c = \frac{\sum_i m_i v_i}{\sum_i m_i}
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| </math>
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| is the velocity of the mass center.
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| The total momentum in the center-of-mass system then vanishes:
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| <math>
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| \sum_{i} p'_i = \sum_{i} m_i v'_i
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| = \sum_{i} m_i (v_i - V_c)
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| = \sum_{i} m_i v_i - \sum_i m_i \frac{\sum_j m_j v_i}{\sum_j m_j}
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| = \sum_i m_i v_i - \sum_j m_j v_j
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| = 0
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| </math>
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| Also, the total [[energy]] of the system is the ''minimal energy'' as seen from all [[inertial reference frame]]s.
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| ===Special relativity===
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| In [[special relativity|relativity]], COM frame exists for a massive system. In the COM frame the total energy of the system is the "[[rest energy]]", and this quantity (when divided by the factor ''c''<sup>2</sup>, where ''c'' is the [[speed of light]]) therefore gives the [[rest mass]] (positive [[invariant mass]]) of the system:
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| :<math> m = \frac{E}{c^2}.</math>
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| The [[invariant mass]] of the system is actually given by the relativistic invariant relation:
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| :<math> m^2 =\left(\frac{E}{c^2}\right)^2-\left(\frac{p}{c}\right)^2 \,\!</math>
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| but for zero momentum the momentum term (''p/c'')<sup>2</sup> vanishes, hence the total energy coincides with the rest energy.
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| Systems which have energy but zero [[invariant mass]] (such as [[photons]] moving in a single direction, or equivalently, [[plane wave|plane]] [[electromagnetic wave]]s) do not have COM frames, because there is no frame which they have zero net momentum. Due to the invariance of the [[speed of light]], such [[Massless particle|massless]] systems must travel at the speed of light in any frame, and therefore always possess a net momentum-magnitude which is equal to their energy divided by the speed of light:
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| :<math> p = E/c. \,\!</math>
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| ==Two-body problem==
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| An example of the usage of this frame is given below – in a two-body collision, not necessarily elastic (where ''kinetic energy'' is conserved). The COM frame can be used to find the momentum of the particles much easier than in a [[lab frame]]: the frame where the measurement or calculation is done. The situation is analyzed using [[Galilean transformations]] and [[conservation of momentum]] (for generality, rather than kinetic energies alone), for two particles of mass ''m''<sub>1</sub> and ''m''<sub>2</sub>, moving at initial velocities (before collision) '''u'''<sub>1</sub> and '''u'''<sub>2</sub> respectively. The transformations are applied to take the velocity of the frame from the velocity of each particle from the lab frame (unprimed quantities) to the COM frame (primed quantities):<ref>Dynamics and Relativity, J.R. Forshaw, A.G. Smith, Wiley, 2009, ISBN 978-0-470-01460-8
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| </ref>
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| :<math>\bold{u}_1^\prime = \bold{u}_1 - \bold{V} , \quad \bold{u}_2^\prime = \bold{u}_2 - \bold{V} </math>
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| where '''V''' is the velocity of the COM frame. Since '''V''' is the velocity of the COM, i.e. the time derivative of the COM location '''R''' (position of the center of mass of the system):<ref>Classical Mechanics, T.W.B. Kibble, European Physics Series, 1973, ISBN 07-084018-0</ref>
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| :<math> \begin{align} | |
| \frac{{\rm d}\bold{R}}{{\rm d}t} & = \frac{{\rm d}}{{\rm d}t}\left(\frac{m_1\bold{r}_1+m_2\bold{r}_2}{m_1+m_2} \right) \\
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| & = \frac{m_1\bold{u}_1 + m_2\bold{u}_2 }{m_1+m_2} \\
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| & = \bold{V} \\
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| \end{align} \,\!</math>
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| so at the origin of the COM frame, '''R''' = '''0''', this implies
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| :<math> m_1\bold{u}_1^\prime + m_2\bold{u}_2^\prime = \boldsymbol{0} </math>
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| The same results can be obtained by applying momentum conservation in the lab frame, where the momenta are '''p'''<sub>1</sub> and '''p'''<sub>2</sub>:
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| :<math>\bold{V} = \frac{\bold{p}_1 + \bold{p}_2}{m_1+m_2} = \frac{m_1\bold{u}_1 + m_2\bold{u}_2}{m_1+m_2}\,\! </math>
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| and in the COM frame, where it is asserted definitively that the total momenta of the particles, '''p'''<sub>1</sub>' and '''p'''<sub>2</sub>', vanishes:
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| :<math> \bold{p}_1^\prime + \bold{p}_2^\prime = m_1\bold{u}_1^\prime + m_2\bold{u}_2^\prime = \boldsymbol{0} </math>
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| Using the COM frame equation to solve for '''V''' returns the lab frame equation above, demonstrating any frame (including the COM frame) may be used to calculate the momenta of the particles. It has been established the velocity of the COM frame can be removed from the calculation using that frame, so the momenta of the particles in the COM frame can be
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| expressed in terms of the quantities in the lab frame (i.e. the given initial values):
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| :<math> \begin{align}
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| \bold{p}_1^\prime & = m_1\bold{u}_1^\prime \\
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| & = m_1 \left( \bold{u}_1 - \bold{V} \right) = \frac{m_1m_2}{m_1+m_2} \left( \bold{u}_1 - \bold{u}_2 \right) \\
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| & = -m_2\bold{u}_2^\prime = -\bold{p}_2^\prime \\
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| \end{align} \,\!</math>
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| notice the [[relative velocity]] in the lab frame of particle 1 to 2 is;
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| :<math> \Delta\bold{u} = \bold{u}_1 - \bold{u}_2 </math>
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| and the 2-body [[reduced mass]] is;
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| :<math> \mu = \frac{m_1m_2}{m_1+m_2} \,\!</math> | |
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| so the momenta of the particles compactly reduce to
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| :<math> \bold{p}_1^\prime = -\bold{p}_2^\prime = \mu \Delta\bold{u} \,\!</math>
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| This is a substantially simpler calculation of the momenta of both particles; the reduced mass and relative velocity can be calculated from the initial velocities in the lab frame and the masses, and the momentum of one particle is simply the negative of the other. The calculation can be repeated for final velocities '''v'''<sub>1</sub> and '''v'''<sub>2</sub> in place of the initial velocities '''u'''<sub>1</sub> and '''u'''<sub>2</sub>, since after the collision the velocities still satisfy the above equations:<ref>''An Introduction to Mechanics'', D. Kleppner, R.J. Kolenkow, Cambridge University Press, 2010, ISBN 978-0-521-19821-9</ref>
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| :<math> \begin{align}
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| \frac{{\rm d}\bold{R}}{{\rm d}t} & = \frac{{\rm d}}{{\rm d}t}\left(\frac{m_1\bold{r}_1+m_2\bold{r}_2}{m_1+m_2} \right) \\
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| & = \frac{m_1\bold{v}_1 + m_2\bold{v}_2 }{m_1+m_2} \\
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| & = \bold{V} \\
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| \end{align} \,\!</math>
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| so at the origin of the COM frame, '''R''' = '''0''', this implies after the collision
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| :<math> m_1\bold{v}_1^\prime + m_2\bold{v}_2^\prime = \boldsymbol{0} </math>
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| In the lab frame, the conservation of momentum fully reads:
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| :<math> m_1\bold{u}_1 + m_2\bold{u}_2 = m_1\bold{v}_1 + m_2\bold{v}_2 = (m_1+m_2)\bold{V}</math>
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| This equation does ''not'' imply that
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| :<math> m_1\bold{u}_1 = m_1\bold{v}_1 = m_1\bold{V}, \quad m_2\bold{u}_2 = m_2\bold{v}_2 = m_2\bold{V}</math>
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| instead, it simply indicates the total mass ''M'' multiplied by the velocity of the centre of mass '''V''' is the total momentum '''P''' of the system:
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| :<math> \begin{align} \bold{P} & = \bold{p}_1 + \bold{p}_2 \\
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| & = (m_1 + m_2)\bold{V} \\
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| & = M\bold{V}
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| \end{align}\,\! </math>
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| Similar analysis to the above obtains;
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| :<math> \bold{p}_1^\prime = -\bold{p}_2^\prime = \mu \Delta\bold{v} = \mu \Delta\bold{u} \,\!</math>
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| where the final [[relative velocity]] in the lab frame of particle 1 to 2 is;
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| :<math> \Delta\bold{v} = \bold{v}_1 - \bold{v}_2 = \Delta\bold{u}.</math>
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| ==See also==
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| *[[Laboratory frame of reference]]
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| ==References==
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| {{reflist}}
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| {{DEFAULTSORT:Center Of Momentum Frame}}
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| [[Category:Classical mechanics]]
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| [[Category:Frames of reference]]
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| [[Category:Kinematics]]
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| [[Category:Coordinate systems]]
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| [[Category:Geometric centers]]
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Oscar is what my wife enjoys to contact me and I completely dig that name. Hiring has been my profession for some time but I've already applied for another one. Years in the past we moved to North Dakota. Body developing is what my family and I enjoy.
Here is my blog post: at home std testing