Arakelov theory: Difference between revisions

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In [[functional analysis]], the '''Dunford–Pettis property''', named after [[Nelson Dunford]] and [[B. J. Pettis]], is a property of a [[Banach space]] stating that all weakly compact operators from this space into another Banach space are completely continuous. Many standard Banach spaces have this property, most notably, the space ''C''(''K'') of continuous functions on a [[compact space]] and the space [[Lp space|''L''<sup>1</sup>(''&mu;'')]] of the Lebesgue integrable functions on a [[measure space]]. [[Alexander Grothendieck]] introduced the concept in the early 1950s {{harv|Grothendieck|1953}}, following the work of [[Dunford]] and Pettis, who developed earlier results of [[Shizuo Kakutani]], [[Kōsaku Yosida]], and several others. Important results were obtained more recently by [[Jean Bourgain]]. Nevertheless, the Dunford–Pettis property is not completely understood.
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== Definition ==
 
A Banach space ''X'' has the '''Dunford–Pettis property''' if every continuous weakly [[compact operator]] ''T'': ''X'' &rarr; ''Y'' from ''X'' into another Banach space ''Y''  transforms weakly compact sets in ''X'' into norm-compact sets in ''Y'' (such operators are called [[completely continuous]]). An important equivalent definition is that for any [[weak topology|weakly convergent]] [[sequence (mathematics)|sequence]]s (''x''<sub>''n''</sub>) of ''X'' and (''f''<sub>''n''</sub>) of the [[dual space]] ''X''<sup>&thinsp;&lowast;</sup>, converging (weakly) to ''x'' and ''f'', the sequence ''f''<sub>''n''</sub>(''x''<sub>''n''</sub>) converges to ''f(x)''.
 
== Counterexamples ==
 
* The second definition may appear counterintuitive at first, but consider an orthonormal basis ''e''<sub>n</sub> of a separable Hilbert space ''H''.  Then ''e''<sub>n</sub> &rarr; 0 weakly, but for all ''n'',
 
::<math>\langle e_n, e_n\rangle = 1.</math>
 
: Thus separable Hilbert spaces cannot have the Dunford–Pettis property.
 
* Consider as another example the space ''L''<sup>''p''</sup>(&minus;&pi;,&pi;) where 1<''p''<∞. The sequences ''x''<sub>n</sub>=''e''<sup>''inx''</sup> in ''L''<sup>''p''</sup> and ''f''<sub>n</sub>=''e''<sup>''inx''</sup> in ''L''<sup>''q''</sup> = (''L''<sup>''p''</sup>)* both converge weakly to zero.  But
 
:: <math>\langle f_n, x_n \rangle = \int_{-\pi}^\pi 1\, dx = 2\pi.</math>
 
* More generally, no infinite-dimensional [[reflexive Banach space]] may have the Dunford–Pettis property. In particular, a [[Hilbert space]] and more generally, [[Lp space]]s with 1 < p < &infin; do not possess this property.
 
== Examples ==
 
* If ''X'' is a [[compact Hausdorff space]], then the Banach space C(''X'') of [[continuous function]]s with the [[uniform norm]] has the Dunford–Pettis property.
 
== References ==
* {{citation|title=On the Dunford–Pettis property|first=Jean|last=Bourgain|authorlink=Jean Bourgain|journal=Proceedings of the American Mathematical Society|volume=81|issue=2|pages=265–272|year=1981|doi=10.2307/2044207|jstor=2044207}}
* {{citation|title=Sur les applications linéaires faiblement compactes d'espaces du type C(K)|journal=Canadian J. Math.|volume=5|year=1953|pages=129–173|first=Alexander|last=Grothendieck|authorlink=Alexander Grothendieck|doi=10.4153/CJM-1953-017-4}}
* {{springer|author=JMF Castillo, SY Shaw|title=Dunford–Pettis property|id=D/d110240}}
* {{citation|title=Köthe-Bochner Function Spaces|first=Pei-Kee|last=Lin|year=2004|publisher=Birkhäuser|
isbn=0-8176-3521-1|url=http://books.google.com/?id=WahnFICUx1AC&pg=PA331&lpg=PA331|oclc=226084233}}
* {{citation|title=Some remarks on the Dunford-Pettis property|journal=[[Rocky Mountain Journal of Mathematics]]|year=1997|volume=27|issue=4|first=Narcisse|last=Randrianantoanina|url=http://rmmc.asu.edu/abstracts/rmj/vol27-4/nrandpag1.pdf}}
 
{{DEFAULTSORT:Dunford-Pettis property}}
[[Category:Banach spaces]]

Latest revision as of 15:01, 5 December 2014

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