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In [[mathematics]], the '''Weierstrass product inequality''' states that given real numbers 0&nbsp;≤&nbsp;''a'', ''b'', ''c'', ''d''&nbsp;≤&nbsp;1, it follows that
 
:<math>(1-a)(1-b)(1-c)(1-d)+a+b+c+d \geq 1. \, </math>
 
The inequality is named after the [[Germany|German]] [[mathematician]] [[Karl Weierstrass]].
 
[[Category:Inequalities]]
 
 
{{mathanalysis-stub}}

Latest revision as of 19:28, 15 March 2013

In mathematics, the Weierstrass product inequality states that given real numbers 0 ≤ a, b, c, d ≤ 1, it follows that

(1a)(1b)(1c)(1d)+a+b+c+d1.

The inequality is named after the German mathematician Karl Weierstrass.


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