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Display information for equation id:math.231144.0 on revision:231144

* Page found: Earnshaw's theorem (eq math.231144.0)

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Hash: 31c80ef69b7967e73cd3b15d05a9b440

TeX (original user input):

\nabla \cdot \mathbf{F} = \nabla \cdot (-\nabla U) = -\nabla^2 U = 0.

TeX (checked):

\nabla \cdot \mathbf {F} =\nabla \cdot (-\nabla U)=-\nabla ^{2}U=0.

LaTeXML (experimental; uses MathML) rendering

MathML (5.13 KB / 947 B) :

𝐅 = ( - U ) = - 2 U = 0 . 𝐅 𝑈 superscript 2 𝑈 0 {\displaystyle\nabla\cdot{\mathbf{F}}=\nabla\cdot(-\nabla U)=-\nabla^{2}U=0.}
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SVG (6.878 KB / 2.274 KB) :

nabla dot bold upper F equals nabla dot left-parenthesis minus nabla upper U right-parenthesis equals minus nabla squared upper U equals 0 period

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MathML (0 B / 8 B) :

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Translations to Computer Algebra Systems

Translation to Maple

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Unknown CAS!

Translation to Mathematica

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Unknown CAS!

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