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Display information for equation id:math.231144.25 on revision:231144

* Page found: Earnshaw's theorem (eq math.231144.25)

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Hash: ab67f1dadb2d4a80eb7743d484256c59

TeX (original user input):

\nabla^2 B_x = {\partial \over \partial x}(\nabla \cdot \mathbf{B}) = 0.

TeX (checked):

\nabla ^{2}B_{x}={\partial  \over \partial x}(\nabla \cdot \mathbf {B} )=0.

LaTeXML (experimental; uses MathML) rendering

MathML (5.01 KB / 1009 B) :

2 B x = x ( 𝐁 ) = 0 . superscript 2 subscript 𝐵 𝑥 𝑥 𝐁 0 {\displaystyle\nabla^{2}B_{x}={\partial\over\partial x}(\nabla\cdot{\mathbf{B}% })=0.}
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SVG (8.094 KB / 2.986 KB) :

nabla squared upper B Subscript x Baseline equals StartFraction partial-differential Over partial-differential x EndFraction times left-parenthesis nabla dot bold upper B right-parenthesis equals 0 period

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Translations to Computer Algebra Systems

Translation to Maple

In Maple:

Unknown CAS!

Translation to Mathematica

In Mathematica:

Unknown CAS!

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