I really wouldn't say [Cayley's theorem] has much to do with it. There is no obvious relation, for a group G, between acting on itself by conjugation and by translation - very different permutation representations.
Charles Matthews 06:43, 23 Aug 2003 (UTC)
Any Lie group is a representation of itself?
This does not sound right. "representation" can refer either to a vector space with an action of a group or to the group morphism from G to GL(V). Neither of these applies here.
Better: any Lie group G acts on itself...
Transport of tangent vectors?
I'm coming at this from a robotics/computer-vision perspective. I don't fully follow the Formal Definition section, but it sounds to me like the adjoint representation of a group element, g, Ad(g), is a linear operator that acts on the vector representation of a tangent vector at the origin, s the way g would operate on the matrix representation, S, of the same tangent vector at the origin. That is,
is equivalent to
up to representation. My sense is that is S parallel transported from the tangent space of the identity to the tangent space of g, and so Ad(g) is doing a similar thing.
Is that even remotely right? Appologies for imprecise lingo. Thanks. —Ben FrantzDale (talk) 15:24, 18 May 2011 (UTC)
Derivative at the origin?
I'm confused by the sentence "It follows that the derivative of Ψg at the identity is an automorphism of the Lie algebra ." Which of these is it referring to (abusing notation)?:
It's probably obvious if you understand this more than I do. :-) 15:56, 9 June 2011 (UTC)
- The following discussion is an archived discussion of a requested move. Please do not modify it. Subsequent comments should be made in a new section on the talk page. Editors desiring to contest the closing decision should consider a move review. No further edits should be made to this section.
The result of the move request was: moved per request. Favonian (talk) 16:10, 21 February 2013 (UTC)
Adjoint representation of a Lie group → Template:No redirect – Per WP:CONCEPTDAB, I believe this article should be located at Adjoint representation, which is currently a disambiguation page. The two concepts are so closely related, they are both defined in the article currently (the adjoint representation of a "Lie group" and a "Lie algebra"), so there is no need for a disambiguation page. Some textbooks define both concepts nearly simultaneously. This has also been discussed at WikiProject Mathematics. Mark M (talk) 17:14, 13 February 2013 (UTC)
- Support. The Lie group and Lie algebra points of view seem so closely connected that it makes sense to have a single article that covers both, and the new name better reflects this unity. —David Eppstein (talk) 18:29, 14 February 2013 (UTC)
- Support per nom and per David Eppstein, whose wisdom on this matter I trust implicitly. bd2412 T 16:31, 15 February 2013 (UTC)
- Thanks, but please note that I am very much not an expert on Lie groups and Lie algebras. —David Eppstein (talk) 01:03, 17 February 2013 (UTC)
- Support -- Taku (talk) 01:35, 21 February 2013 (UTC)
- The above discussion is preserved as an archive of a requested move. Please do not modify it. Subsequent comments should be made in a new section on this talk page or in a move review. No further edits should be made to this section.
Is really Ad : G -> Aut(g) for any Lie group G?
If Aut(g) are the automorphism of the Lie algebra g, that is linear operators preserving the Lie brackets, does Ad really associates to any element of G an element of Aut(g)?
Is it possible that this holds only if G is a group of matrices for which holds the nice formula Ad_x (a) = x a x^(-1), (x is in G, a is in g), whilst in the most general situation G is sent by Ad into linear operators g -> g (not Lie bracket preserving)?
I'm probably wrong, it has been a while since i've studied this stuff. — Preceding unsigned comment added by 22.214.171.124 (talk) 22:32, 11 December 2013 (UTC)