|
|
| (655 intermediate revisions by more than 100 users not shown) |
| Line 1: |
Line 1: |
| In [[electrical engineering]], the '''maximum power transfer theorem''' states that, to obtain ''maximum'' external power from a source with a finite [[internal resistance]], the resistance of the load must equal the resistance of the source as viewed from its output terminals. [[Moritz von Jacobi]] published the maximum power (transfer) theorem around 1840; it is also referred to as "Jacobi's law".<ref>{{citation |url=http://books.google.com/?id=dKVbT-ZmdDwC&pg=PA406 |title=Dynamo-Electric Machinery; A Manual for Students of Electrotechnics |author=Thompson Phillips |publisher=BiblioBazaar, LLC |isbn=978-1-110-35104-6 |date=2009-05-30}}</ref>
| | This is a preview for the new '''MathML rendering mode''' (with SVG fallback), which is availble in production for registered users. |
|
| |
|
| The [[theorem]] results in maximum ''[[Electric power|power]]'' transfer, and not maximum ''[[efficiency]]''. If the [[Electrical resistance|resistance]] of the load is made larger than the resistance of the source, then efficiency is higher, since a higher percentage of the source power is transferred to the load, but the ''magnitude'' of the load power is lower since the total circuit resistance goes up.
| | If you would like use the '''MathML''' rendering mode, you need a wikipedia user account that can be registered here [[https://en.wikipedia.org/wiki/Special:UserLogin/signup]] |
| | * Only registered users will be able to execute this rendering mode. |
| | * Note: you need not enter a email address (nor any other private information). Please do not use a password that you use elsewhere. |
|
| |
|
| If the load resistance is smaller than the source resistance, then most of the power ends up being dissipated in the source, and although the total power dissipated is higher, due to a lower total resistance, it turns out that the amount dissipated in the load is reduced.
| | Registered users will be able to choose between the following three rendering modes: |
|
| |
|
| The theorem states how to choose (so as to maximize power transfer) the load resistance, once the source resistance is given. It is a common misconception to apply the theorem in the opposite scenario. It does ''not'' say how to choose the source resistance for a given load resistance. In fact, the source resistance that maximizes power transfer is always zero, regardless of the value of the load resistance.
| | '''MathML''' |
| | :<math forcemathmode="mathml">E=mc^2</math> |
|
| |
|
| The theorem can be extended to [[alternating current]] circuits that include [[Electrical reactance|reactance]], and states that maximum power transfer occurs when the load [[Electrical impedance|impedance]] is equal to the [[complex conjugate]] of the source impedance.
| | <!--'''PNG''' (currently default in production) |
| | :<math forcemathmode="png">E=mc^2</math> |
|
| |
|
| == Maximizing power transfer versus power efficiency == | | '''source''' |
| The theorem was originally misunderstood (notably by [[James Prescott Joule|Joule]]) to imply that a system consisting of an electric motor driven by a battery could not be more than 50% efficient since, when the impedances were matched, the power lost as heat in the battery would always be equal to the power delivered to the motor. In 1880 this assumption was shown to be false by either [[Thomas Edison|Edison]] or his colleague [[Francis Robbins Upton]], who realized that maximum efficiency was not the same as maximum power transfer. To achieve maximum efficiency, the resistance of the source (whether a battery or a [[dynamo]]) could be made close to zero. Using this new understanding, they obtained an efficiency of about 90%, and proved that the [[electric motor]] was a practical alternative to the [[heat engine]].
| | :<math forcemathmode="source">E=mc^2</math> --> |
|
| |
|
| [[File:Source and load circuit.png]] [[File:Maximum Power Transfer Graph.svg]] | | <span style="color: red">Follow this [https://en.wikipedia.org/wiki/Special:Preferences#mw-prefsection-rendering link] to change your Math rendering settings.</span> You can also add a [https://en.wikipedia.org/wiki/Special:Preferences#mw-prefsection-rendering-skin Custom CSS] to force the MathML/SVG rendering or select different font families. See [https://www.mediawiki.org/wiki/Extension:Math#CSS_for_the_MathML_with_SVG_fallback_mode these examples]. |
|
| |
|
| The condition of maximum power transfer does not result in maximum [[Electrical efficiency|efficiency]]. If we define the efficiency {{math|''η''}} as the ratio of power dissipated by the load to power developed by the source, then it is straightforward to calculate from the above circuit diagram that
| | ==Demos== |
|
| |
|
| :<math>\eta = \frac{R_\mathrm{load}}{R_\mathrm{load} + R_\mathrm{source}} = \frac{1}{1 + R_\mathrm{source} / R_\mathrm{load}}.</math> | | Here are some [https://commons.wikimedia.org/w/index.php?title=Special:ListFiles/Frederic.wang demos]: |
|
| |
|
| Consider three particular cases:
| |
|
| |
|
| * If <math>R_\mathrm{load} = R_\mathrm{source}</math>, then <math>\eta = 0.5,</math> | | * accessibility: |
| * If <math>R_\mathrm{load} = \infty</math> or <math>R_\mathrm{source} = 0,</math> then <math>\eta = 1,</math> | | ** Safari + VoiceOver: [https://commons.wikimedia.org/wiki/File:VoiceOver-Mac-Safari.ogv video only], [[File:Voiceover-mathml-example-1.wav|thumb|Voiceover-mathml-example-1]], [[File:Voiceover-mathml-example-2.wav|thumb|Voiceover-mathml-example-2]], [[File:Voiceover-mathml-example-3.wav|thumb|Voiceover-mathml-example-3]], [[File:Voiceover-mathml-example-4.wav|thumb|Voiceover-mathml-example-4]], [[File:Voiceover-mathml-example-5.wav|thumb|Voiceover-mathml-example-5]], [[File:Voiceover-mathml-example-6.wav|thumb|Voiceover-mathml-example-6]], [[File:Voiceover-mathml-example-7.wav|thumb|Voiceover-mathml-example-7]] |
| * If <math>R_\mathrm{load} = 0</math>, then <math>\eta = 0.</math> | | ** [https://commons.wikimedia.org/wiki/File:MathPlayer-Audio-Windows7-InternetExplorer.ogg Internet Explorer + MathPlayer (audio)] |
| | ** [https://commons.wikimedia.org/wiki/File:MathPlayer-SynchronizedHighlighting-WIndows7-InternetExplorer.png Internet Explorer + MathPlayer (synchronized highlighting)] |
| | ** [https://commons.wikimedia.org/wiki/File:MathPlayer-Braille-Windows7-InternetExplorer.png Internet Explorer + MathPlayer (braille)] |
| | ** NVDA+MathPlayer: [[File:Nvda-mathml-example-1.wav|thumb|Nvda-mathml-example-1]], [[File:Nvda-mathml-example-2.wav|thumb|Nvda-mathml-example-2]], [[File:Nvda-mathml-example-3.wav|thumb|Nvda-mathml-example-3]], [[File:Nvda-mathml-example-4.wav|thumb|Nvda-mathml-example-4]], [[File:Nvda-mathml-example-5.wav|thumb|Nvda-mathml-example-5]], [[File:Nvda-mathml-example-6.wav|thumb|Nvda-mathml-example-6]], [[File:Nvda-mathml-example-7.wav|thumb|Nvda-mathml-example-7]]. |
| | ** Orca: There is ongoing work, but no support at all at the moment [[File:Orca-mathml-example-1.wav|thumb|Orca-mathml-example-1]], [[File:Orca-mathml-example-2.wav|thumb|Orca-mathml-example-2]], [[File:Orca-mathml-example-3.wav|thumb|Orca-mathml-example-3]], [[File:Orca-mathml-example-4.wav|thumb|Orca-mathml-example-4]], [[File:Orca-mathml-example-5.wav|thumb|Orca-mathml-example-5]], [[File:Orca-mathml-example-6.wav|thumb|Orca-mathml-example-6]], [[File:Orca-mathml-example-7.wav|thumb|Orca-mathml-example-7]]. |
| | ** From our testing, ChromeVox and JAWS are not able to read the formulas generated by the MathML mode. |
|
| |
|
| The efficiency is only 50% when maximum power transfer is achieved, but approaches 100% as the load resistance approaches infinity, though the total power level tends towards zero. Efficiency also approaches 100% if the source resistance approaches zero, and 0% if the load resistance approaches zero. In the latter case, all the power is consumed inside the source (unless the source also has no resistance), so the power dissipated in a [[short circuit]] is zero.
| | ==Test pages == |
|
| |
|
| ==Impedance matching==
| | To test the '''MathML''', '''PNG''', and '''source''' rendering modes, please go to one of the following test pages: |
| {{main|impedance matching}}
| | *[[Displaystyle]] |
| A related concept is reflectionless [[impedance matching]]. In [[radio]], [[transmission line]]s, and other [[electronics]], there is often a requirement to match the [[source impedance]] (such as a transmitter) to the [[load impedance]] (such as an [[antenna (electronics)|antenna]]) to avoid reflections in the [[transmission line]].
| | *[[MathAxisAlignment]] |
| | *[[Styling]] |
| | *[[Linebreaking]] |
| | *[[Unique Ids]] |
| | *[[Help:Formula]] |
|
| |
|
| == Calculus-based proof for purely resistive circuits ==
| | *[[Inputtypes|Inputtypes (private Wikis only)]] |
| (See Cartwright<ref>{{citation
| | *[[Url2Image|Url2Image (private Wikis only)]] |
| |last=Cartwright
| | ==Bug reporting== |
| |first=Kenneth V
| | If you find any bugs, please report them at [https://bugzilla.wikimedia.org/enter_bug.cgi?product=MediaWiki%20extensions&component=Math&version=master&short_desc=Math-preview%20rendering%20problem Bugzilla], or write an email to math_bugs (at) ckurs (dot) de . |
| |title=Non-Calculus Derivation of the Maximum Power Transfer Theorem
| |
| |journal=Technology Interface
| |
| |volume=8
| |
| |issue=2
| |
| |pages=19 pages
| |
| |date=Spring 2008
| |
| | |
| |url=http://technologyinterface.nmsu.edu/Spring08/
| |
| }}</ref> for a non-calculus-based proof)
| |
|
| |
| [[File:maxpowertheorem.png|left|Circuit diagram]] | |
| | |
| In the diagram opposite, power is being transferred from the source, with voltage {{math|''V''}} and fixed [[source resistance]] {{math|''R''<sub>S</sub>}}, to a load with resistance {{math|''R''<sub>L</sub>}}, resulting in a current {{math|''I''}}. By [[Ohm's law]], {{math|''I''}} is simply the source voltage divided by the total circuit resistance:
| |
| | |
| :<math>I = \frac{V}{R_\mathrm{S} + R_\mathrm{L}}.</math>
| |
| | |
| The power {{math|''P''<sub>L</sub>}} dissipated in the load is the square of the current multiplied by the resistance:
| |
| | |
| :<math>P_\mathrm{L} = I^2 R_\mathrm{L} = \left(\frac{V}{R_\mathrm{S} + R_\mathrm{L}}\right)^2 R_\mathrm{L} = \frac{V^2}{R_\mathrm{S}^2 / R_\mathrm{L} + 2 R_\mathrm{S} + R_\mathrm{L}}.</math>
| |
| | |
| The value of {{math|''R''<sub>L</sub>}} for which this expression is a maximum could be calculated by differentiating it, but it is easier to calculate the value of {{math|''R''<sub>L</sub>}} for which the denominator
| |
| | |
| :<math>R_\mathrm{S}^2 / R_\mathrm{L} + 2 R_\mathrm{S} + R_\mathrm{L}</math>
| |
| | |
| is a minimum. The result will be the same in either case. Differentiating the denominator with respect to {{math|''R''<sub>L</sub>}}:
| |
| | |
| :<math>
| |
| \frac{d}{d R_\mathrm{L}} \left(R_\mathrm{S}^2 / R_\mathrm{L} + 2R_\mathrm{S} + R_\mathrm{L}\right) = -R_\mathrm{S}^2 / R_\mathrm{L}^2 + 1.</math>
| |
| | |
| For a maximum or minimum, the first derivative is zero, so
| |
| | |
| :<math>
| |
| R_\mathrm{S}^2 / R_\mathrm{L}^2 = 1</math>
| |
| | |
| or
| |
| | |
| :<math>R_\mathrm{L} = \pm R_\mathrm{S}.</math>
| |
| | |
| In practical resistive circuits, {{math|''R''<sub>S</sub>}} and {{math|''R''<sub>L</sub>}} are both positive, so the positive sign in the above is the correct solution. To find out whether this solution is a minimum or a maximum, the denominator expression is differentiated again:
| |
| | |
| :<math>{{d^2} \over {dR_\mathrm{L}^2}} \left( {R_\mathrm{S}^2 / R_\mathrm{L} + 2 R_\mathrm{S} + R_\mathrm{L}} \right) = {2 R_\mathrm{S}^2} / {R_\mathrm{L}^3}. \,\!</math>
| |
| | |
| This is always positive for positive values of <math>R_\mathrm{S} \,\!</math> and <math>R_\mathrm{L} \,\!</math>, showing that the denominator is a minimum, and the power is therefore a maximum, when
| |
| | |
| :<math>R_\mathrm{S} = R_\mathrm{L}. \,\!</math>
| |
| | |
| A note of caution is in order here. This last statement, as written, implies to many people that for a given load, the source resistance must be set equal to the load resistance for maximum power transfer. However, this equation only applies if the source resistance cannot be adjusted, e.g., with antennas (see the first line in the proof stating "fixed source resistance"). For any given load resistance a source resistance of zero is the way to transfer maximum power to the load. As an example, a 100 volt source with an internal resistance of 10 ohms connected to a 10 ohm load will deliver 250 watts to that load. Make the source resistance zero ohms and the load power jumps to 1000 watts.
| |
| | |
| ==In reactive circuits== | |
| The theorem also applies where the source and/or load are not totally resistive. This invokes a refinement of the maximum power theorem, which says that any reactive components of source and load should be of equal magnitude but opposite phase. (''See below for a derivation.'') This means that the source and load impedances should be ''[[complex conjugate]]s'' of each other. In the case of purely resistive circuits, the two concepts are identical. However, physically realizable sources and loads are not usually totally resistive, having some inductive or capacitive components, and so practical applications of this theorem, under the name of complex conjugate impedance matching, do, in fact, exist.
| |
| | |
| If the source is totally inductive (capacitive), then a totally capacitive (inductive) load, in the absence of resistive losses, would receive 100% of the energy from the source but send it back after a quarter cycle. The resultant circuit is nothing other than a resonant [[LC circuit]] in which the energy continues to oscillate to and fro. This is called [[reactive power]]. [[Power factor correction]] (where an inductive reactance is used to "balance out" a capacitive one), is essentially the same idea as complex conjugate impedance matching although it is done for entirely different reasons.
| |
| | |
| For a fixed reactive ''source'', the maximum power theorem maximizes the real power (P) delivered to the load by complex conjugate matching the load to the source.
| |
| | |
| For a fixed reactive ''load'', power factor correction minimizes the [[apparent power]] (S) (and unnecessary current) conducted by the transmission lines, while maintaining the same amount of real power transfer. This is done by adding a reactance to the load to balance out the load's own reactance, changing the reactive load impedance into a resistive load impedance.
| |
| | |
| === Proof ===
| |
| | |
| [[File:Source and load boxes.png|left|source and load impedance diagram]]
| |
| | |
| In this diagram, [[AC power]] is being transferred from the source, with [[phasor (electronics)|phasor]] magnitude voltage <math>|V_\mathrm{S}|</math> (peak voltage) and fixed [[source impedance]] <math>Z_\mathrm{S}</math>, to a load with impedance <math>Z_\mathrm{L}</math>, resulting in a phasor magnitude current <math>|I|</math>. <math>|I|</math> is simply the source voltage divided by the total circuit impedance:
| |
| | |
| :<math>
| |
| |I| = { |V_\mathrm{S}| \over |Z_\mathrm{S} + Z_\mathrm{L}| }.
| |
| </math>
| |
| | |
| The average power <math>P_\mathrm{L}</math> dissipated in the load is the square of the current multiplied by the resistive portion (the real part) <math>R_\mathrm{L}</math> of the load impedance:
| |
| | |
| : <math>
| |
| \begin{align}
| |
| P_\mathrm{L} & = I_\mathrm{rms}^2 R_\mathrm{L} = {1 \over 2} |I|^2 R_\mathrm{L} = {1 \over 2} \left( {|V_\mathrm{S}| \over |Z_\mathrm{S} + Z_\mathrm{L}|} \right)^2 R_\mathrm{L} \\
| |
| & = {1 \over 2}{ |V_\mathrm{S}|^2 R_\mathrm{L} \over (R_\mathrm{S} + R_\mathrm{L})^2 + (X_\mathrm{S} + X_\mathrm{L})^2}, | |
| \end{align}
| |
| </math>
| |
| | |
| where the resistance <math>R_\mathrm{S}</math> and reactance <math>X_\mathrm{S}</math> are the real and imaginary parts of <math>Z_\mathrm{S}</math>, and <math>X_\mathrm{L}</math> is the imaginary part of <math>Z_\mathrm{L}</math>.
| |
| | |
| To determine the values of <math>R_\mathrm{L}</math> and <math>X_\mathrm{L}</math> (since <math>V_\mathrm{S}</math>, <math>R_\mathrm{S}</math>, and <math>X_\mathrm{S}</math> are fixed) for which this expression is a maximum, we first find, for each fixed positive value of <math>R_\mathrm{L}</math>, the value of the reactive term <math>X_\mathrm{L}</math> for which the denominator
| |
| | |
| :<math>
| |
| (R_\mathrm{S} + R_\mathrm{L})^2 + (X_\mathrm{S} + X_\mathrm{L})^2 \,
| |
| </math>
| |
| | |
| is a minimum. Since reactances can be negative, this denominator is easily minimized by making
| |
| | |
| :<math>
| |
| X_\mathrm{L} = -X_\mathrm{S}.\,
| |
| </math>
| |
| | |
| The power equation is now reduced to:
| |
| | |
| :<math>
| |
| P_\mathrm{L} = {1 \over 2}{{|V_\mathrm{S}|^2 R_\mathrm{L}}\over{(R_\mathrm{S} + R_\mathrm{L})^2}}\,\!
| |
| </math>
| |
| | |
| and it remains to find the value of <math>R_\mathrm{L}</math> which maximizes this expression. However, this maximization problem has exactly the same form as in the purely resistive case, and the maximizing condition <math>R_\mathrm{L} = R_\mathrm{S}</math> can be found in the same way.
| |
| | |
| The combination of conditions
| |
| | |
| *<math>R_\mathrm{L} = R_\mathrm{S}\,\!</math>
| |
| *<math>X_\mathrm{L} = -X_\mathrm{S}\,\!</math>
| |
| | |
| can be concisely written with a [[complex conjugate]] (the *) as:
| |
| | |
| :<math>Z_\mathrm{L} = Z_\mathrm{S}^*.</math>
| |
| | |
| ==Notes==
| |
| <references/>
| |
| | |
| ==References==
| |
| *H.W. Jackson (1959) Introduction to Electronic Circuits, Prentice-Hall.
| |
| | |
| == External links ==
| |
| * [http://www.ece.rutgers.edu/~orfanidi/ewa/ch12.pdf ''Conjugate matching versus reflectionless matching''] ([[PDF]]) taken from [http://www.ece.rutgers.edu/~orfanidi/ewa/ ''Electromagnetic Waves and Antennas'']
| |
| * [http://home.freeuk.net/dunckx/wireless/maxpower1/maxpower1.html ''The Spark Transmitter. 2. Maximising Power, part 1.'']
| |
| * [http://www.du.edu/~jcalvert/tech/jacobi.htm ''Jacobi's theorem''] - unconfirmed claim that theorem was discovered by Moritz Jacobi
| |
| * [http://chem.ch.huji.ac.il/~eugeniik/history/jacobi.html] MH Jacobi Biographical notes
| |
| * [http://spreadsheets.google.com/pub?key=pANWpjmy2L4xC96TaLF6MEA Google Docs Spreadsheet] calculating max power transfer efficiencies by Sholto Maud and Dino Cevolatti.
| |
| | |
| [[Category:Circuit theorems]]
| |
| [[Category:Electrical engineering]]
| |
| | |
| [[de:Leistungsanpassung]]
| |
| [[es:Teorema de máxima potencia]]
| |
| [[fr:Adaptation d'impédances]]
| |
| [[hi:अधिकतम शक्ति का प्रमेय]]
| |
| [[pl:Dopasowanie energetyczne]]
| |
| [[fi:Maksimitehonsiirtolause]]
| |
| [[uk:Теорема максимальної потужності (теорема Якобі)]]
| |
